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Ivanshal [37]
3 years ago
13

50 pts + Brainliest Please help [email p

rotected]

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
4 0
The answer is 2712.96 but you have to round so it's 2713.
LiRa [457]3 years ago
3 0
The radius of the cylinder's base is 8, so the volume of the cylinder is \pi8^218\approx3617.28 (using the approximation of \pi\approx3.14).

The sphere has radius 6, so the volume of the sphere is \dfrac43\pi6^3\approx904.32.

The volume of the shaded region is the difference between the two: 3617.28 - 904.32 = 2712.96. Rounded to the nearest integer gives an answer of 2713.
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grandymaker [24]

Answer:

18

Step-by-step explanation:

5 0
3 years ago
A lot is in the shape of a triangle. One side is 100 ft longer than the shortest side, while the third side is 700 ft longer tha
vaieri [72.5K]

We have the next information

x= the shortest side measure

y= the second side measure

y=x+100

z= the third side measures

z=x+700

We know also that the perimeter is 2900 ft

Therefore the equation for the perimeter of the triangle will be

P=x+y+z2900=x+x+100+x+700

we sum like terms

2900=3x+800

then we isolate the x

3x=2900-8003x=2100x=\frac{2100}{3}=700

therefore

x=700ft

y=700+100=800ft

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The lengths of the sides of the lote are 700 ,800, and 1400 ft,

8 0
1 year ago
Help please thank you!
ozzi
4x^2 + 16x-2= 5x
Minus 16x over

4x2-2= -11x

Add 11x over

4x^2 +11x -2

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I’m not sure here. I tried my best. Hope it helps!
8 0
3 years ago
Read 2 more answers
Help with these two math questions thank u :)
Tju [1.3M]

Answer:

1.) - (4, 4)    2.) - (3,5) Hope this helps!!

4 0
3 years ago
A circle has been split into 8 sectors each of which can be colored as 4 different colors, and no consecutive sectors are colore
Eva8 [605]

Answer:

5832 ways

Step-by-step explanation:

Since the circle has 8 sectors and there is 4 colour,

Assuming the sectors are numbered 1 to 8,

Sector 1 : can be coloured with any of the 4 colour in 4 ways

Sector 2 can be coloured with any of the remaining 3 colours in 3 ways

Sector 3 in 3 ways without using the colour in sector 2

Sector 4 in 3 ways without using the colour in sector 3

Sector 5 in 3 ways without using the colour in sector 4

Sector 6 in 3 ways without using the colour in sector 5

Sector 7 in 3 ways without using the colour in sector 6

Sector 8 in 2 ways without using the colours in sector 1 and 7

Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways

3 0
3 years ago
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