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lord [1]
3 years ago
8

Tennis balls are sold in cylindrical cans with the balls stacked one on top of the other. A tennis ball has a diameter of 6.7 cm

. To the nearest cubic centimeter, what is the minimum volume of the can that holds a stack of 4 tennis balls
Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

629.92 cm^3

Step-by-step explanation:

The minimum volume of the can that can hold 4 tennis balls must have at least the same volume as 4 tennis balls.

The volume of one tennis ball, V = \frac{4}{3}\pi  r^3

where r = radius of the tennis ball

The diameter of a ball = 6.7 cm

Its radius will be = 6.7 / 2 = 3.35 cm

Volume, V, will be:

V = \frac{4}{3}\pi  (3.35)^3

V = 157.48cm^3

Hence, the volume of 4 balls will be:

4 * V = 4 * 157.48 = 629.92 cm^3

The minimum volume that the cylindrical can has to have is 629.92 cm^3.

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Stels [109]

Hey there!

x^0

Anything to the power of 0 is 1. So that means x can be equal to any number. Let's say 1^0, it will still equal 1. 2^0 is also equal to 1. X is therefore not a number since it can be anything.

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Hope this helps!

AT2309

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shusha [124]

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The number of outcomes that have a product less than 30 and contain at least one odd number is shown below. These outcomes are outcomes circled in both cases shown above,

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