Question

Tennis balls are sold in cylindrical cans with the balls stacked one on top of the other. A tennis ball has a diameter of 6.7 cm. To the nearest cubic centimeter, what is the minimum volume of the can that holds a stack of 4 tennis balls

Answer 1

Answer:

629.92 $cm^3$

Step-by-step explanation:

The minimum volume of the can that can hold 4 tennis balls must have at least the same volume as 4 tennis balls.

The volume of one tennis ball, V = $\frac{4}{3}\pi r^3$

where r = radius of the tennis ball

The diameter of a ball = 6.7 cm

Its radius will be = 6.7 / 2 = 3.35 cm

Volume, V, will be:

$V = \frac{4}{3}\pi (3.35)^3$

V = 157.48$cm^3$

Hence, the volume of 4 balls will be:

4 * V = 4 * 157.48 = 629.92 $cm^3$

The minimum volume that the cylindrical can has to have is 629.92 $cm^3$.