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3 years ago

Which of the following is algebraically equivalent to the sum of 4x^2 -8x +7 And 3x^2-2x-5

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

5 0

All you have to do, is combine like terms. Let's go through it:

$(4x^2-8x+7)+(3x^2-2x-5)$

Arrange it so you can easily combine like terms:

$4x^2+3x^2-8x-2x+7-5 = 7x^2-10x+2$

So, your answer for the sum is 1) 7x² - 10x + 2

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Springfield nuclear energy inc bonds are currently trading at 283.30. The bonds have a face value of $1,000, a coupon rate of 2%

vampirchik [111]

<u>Answer:</u>

The yield to maturity of the bonds is 11%

<u>Explanation:</u>

Price at which the bonds is currently trading = 283.30$

Face Value = $1000

Coupon rate = 2%

Hence the coupon bond rate = $1000 ×2%

= $1000\times \frac{2}{100}$

=$20

Years to maturity: 20 years

Formula used:

= $\frac{(C+ (\frac{(F-P)}{n}))}{(\frac{(F+P)}{2})}$

Where C is the bond coupon rate

F is the face value

P is the price

N is the number of years

= $\frac{(20 +(\frac{(1000-283.30)}{20})}{(\frac{(1000+283.30)}{2})}$

=11%

The yield to maturity of the bonds is 11%

3 0

3 years ago

4/5,9/10,17/20 least to greatest

Lana71 [14]

Answer: 4/5 17/20 9/10

Step-by-step explanation:

Find a common denominator

4/5-16/20

17/20-17/20

9/10-18/20

6 0

3 years ago

Read 2 more answers

One grain of this sand approximately weighs 6 x 10^-6g.

emmasim [6.3K]

Answer:

1.2×10¹² grains

Step-by-step explanation:

1 grain = 6×10⁻⁶ g

7200 kg =
7200000 g =
7.2×10⁶ g =
7.2×10⁶ ÷ 6×10⁻⁶ =
(7.2÷6)×10⁶⁻ ⁽⁻⁶⁾ =
1.2×10¹² grains

4 0

2 years ago

Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc

Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

$\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m$

To find:

$\textrm{final velocity} = v = ?$

Solution:

As we know the third equation of motion is represented as

$v^{2} = u^{2} + 2\times a\times s\\$

Substituting the values u, a and s in the above equation we get

$v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\$

$v =\±\sqrt{473} \\v =\sqrt{473} \ \textrm{as acceleration is positive v is also positive}\\v = 21.74\ m/s$

7 0

3 years ago

What are the steps to solve this problem?

adoni [48]

I'm sorry you need to be more clear I don't understand the question.

7 0

3 years ago