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3 years ago

Graphing a line given it’s equation in standard form

Mathematics

1 answer:

S_A_V [24]3 years ago

4 0

You'd first change the equation to slope-intercept form.

For example:

-2x + y = 6

You'd add 2x to both sides -

-2x + y + <u>2x</u> = 6 + <u>2x </u>

y = 2x + 6

So you'd graph y = 2x + 6

___

Hope this helped!

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Can someone help with this problem on literal equations to get variable A by itself? Will give lots of points

-BARSIC- [3]

Answer:

Step-by-step explanation:

Part A

xf = xo + vo* t + 1/2 a*t^2 Subtract xo

xf - xo = 0*t + 1/2 a*t^2 multiply by 2

2(xf - xo) = at^2 divide by t^2

2(xf - xo ) / t^2 = a

Part B

Givens

xo =0

vo = 0

a = 10 m/s^2

xf = 120 m

Solution

xf = xo + vo* t + 1/2 a*t^2 Substitute the givens

120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2

120*2 = 10* t^2

240 = 10*t^2 Divide by 10

240/10 = t^2

24 = t^2 take the square root of both sides.

√24 = √t^2

t = √24

t = √(2 * 2 * 2 * 3)

t = 2√6

8 0

3 years ago

Two sides of a rectangle differ by 3.5cm.Find the dimensions of the rectangle if its perimeter is 67cm.

Margaret [11]

Answer:

Sides are x and x + 3.5 cm

Perimeter = 2(x + (x + 3.5))cm

4x +7 = 67

x = 15cm Answer

Step-by-step explanation:

HOPE THIS HELPED!

8 0

3 years ago

Read 2 more answers

William went shopping for a new phone because of a sale. The store was offering a 15% discount. If the price on the tag was $41,

Alik [6]

Answer:

*WILLIAM AFTON*

Real Answer:

38 dollars and 11 cents.

3 0

3 years ago

Arectangularplotoflandistobefencedinusingtwokinds of fencing. Two opposite sides will use heavy-duty fencing selling for $3 a fo

svlad2 [7]

Answer:

Dimensions of the rectangular plot will be 500 ft by 750 ft.

Step-by-step explanation:

Let the length of the rectangular plot = x ft.

and the width of the plot = y ft.

Cost to fence the length at the cost $3.00 per feet = 3x

Cost to fence the width of the cost $2.00 per feet = 2y

Total cost to fence all sides of rectangular plot = 2(3x + 2y)

2(3x + 2y) = 6,000

3x + 2y = 3,000 ----------(1)

3x + 2y = 3000

2y = 3000 - 3x

y = $\frac{1}{2}[3000-3x]$

y = 1500 - $\frac{3x}{2}$

Now area of the rectangle A = xy square feet

A = x[ $1500-\frac{3x}{2}$ ]

For maximum area $\frac{dA}{dx}=0$

A' = $\frac{d}{dx}(1500x-\frac{3}{2}x^{2})$ = 0

1500 - 3x = 0

3x = 1500

x = 500 ft

From equation (1),

y = 1500 - $\frac{3}{2}\times 500$

y = 1500 - 750

y = 750 ft

Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.

two fencing 3(500+500) = $3000

other two fencing 2(750+750) = $3000

8 0

3 years ago

Solve by using Pythagorean Theorem, a= 5, b= x-1, and c=x

charle [14.2K]

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

Step-by-step explanation:

The given is,

a = 5

b = x - 1

c = x

Step:1

Pythagorean theorem is,

$a^{2} + b^{2} = c^{2}$ ................................(1)

( It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides )

From the given values the equation (1) becomes,

$5^{2} + (x-1) ^{2} = x^{2}$

( $(a-b)^{2} = a^{2} + b^{2} -2ab$ )

25 + ( $x^{2}$ + 1 - 2x ) = $x^{2}$

25 + 1 -2x = 0 ( ∵ Eliminate $x^{2}$ in both sides)

26 = 2x

x = 13

Step:2

From the values of x,

a = 5

b = ( 13 - 1 ) = 12

c = 13

Result:

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

3 0

3 years ago