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KatRina [158]
3 years ago
15

Which expression is half as large as the expression 46+42

Mathematics
1 answer:
Andrej [43]3 years ago
7 0
Well, 46+42=88 and that divided by 2 is 44. So there ya go.
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Please help me answer this please!!
Assoli18 [71]
I think the answer is 15
8 0
3 years ago
100-99+98-97+96-95...2-1=
Simora [160]
100-99=1+98=99-97=2+96=98-95=3
2-1=1
5 0
3 years ago
What is the value of A, B, and C?
Varvara68 [4.7K]

Answer: a's value is (6,8) B is (-3,7), and C is (-7,-2)

4 0
3 years ago
-4x-3(-44-23)=13<br><br><br> please show the work, i’ll mark brainliest
pychu [463]

Answer:

47

Step-by-step explanation:

Let's solve your equation step-by-step.

−4x−3(−44−23)=13

Step 1: Simplify both sides of the equation.

−4x+201=13

Step 2: Subtract 201 from both sides.

−4x+201−201=13−201

−4x=−188

Step 3: Divide both sides by -4.

−4x

−4

=

−188

−4

x=47

3 0
2 years ago
Osama starts with a population of 1,000 amoebas that increases 30% in size every hour for a number of hours, h. The expression 1
Blizzard [7]

Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.

Explanation:

From the given information,

Initial population = 1000

Increasing rate or growth rate = 30% every hour.

No of population increase in every hour is,

1000\times \frac{30}{100} =1000\times 0.3

Total population after h hours is,

1000(1+0.3)^h

It is in the form of,

P(t)=P_0(t)(1+r)^t

Where P_0(t) is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex]  is the growth factor after time t.

In the above equation 1000 is the initial population and (1+0.3)^h is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.

Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.

3 0
3 years ago
Read 2 more answers
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