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3 years ago

15

Which expression is half as large as the expression 46+42

1 answer:

Andrej [43]3 years ago

7 0

Well, 46+42=88 and that divided by 2 is 44. So there ya go.

You might be interested in

Graph the function g(x) = 1/3 - 4/3x

True [87]

  Solutions

g(x) = $\frac{1}{3}$ - $\frac{4}{3}$ x

  g(x) = - <span> $\frac{4}{3}$ x + $\frac{1}{3}$

x = -5

= </span>g(x) = - $\frac{4}{3}$ × (-5) + <span> $\frac{1}{3}$
</span>
= $\frac{20}{3}$ + <span> $\frac{1}{3}$
</span>
= $\frac{21}{3}$

= 7

(-5,7)

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x = 7

  = g(x) = - $\frac{4}{3}$ × (7) +  <span> $\frac{1}{3}$
</span>
= $\frac{-28}{3}$ + <span> $\frac{1}{3}$
</span>
= $\frac{-27}{3}$ = -9

(-7,9)

x = (-7,9)   y = <span>(-5,7)</span>

6 0

3 years ago

Before going to school, Eudora ran from her home to a secret laboratory at an average speed of 12 km. Since she was running late

Brrunno [24]

Answer:

Eudora spent 0.5 hours in running and 1.5 hours flying using her jet-pack.

Step-by-step explanation:

Let x represent time spent in running.

We have been given that the entire trip took 2 hours, so time spent in flying the jet-packs would be $2-x$ .

We know that distance is equal to speed times time.

$\text{Distance}=\text{Speed}\times\text{Time}$

Eudora ran from her home to a secret laboratory at an average speed of 12 km, so distance traveled by running would be $12x$ .

Eudora took one of her jet-packs and flew to her school at an average speed of 76 km, so distance covered by jet-packs would be $76(2-x)$ .

We are told that Eudora traveled a total distance of 120 km. We can represent this information in an equation as:

$12x+76(2-x)=120$

$12x+152-76x=120$

Combine like terms:

$-64x+152=120$

$-64x+152-152=120-152$

$-64x=-32$

Divide both sides by $-64$ :

$\frac{-64x}{-64}=\frac{-32}{-64}$

$x=0.5$

Therefore, Eudora spent 0.5 hours in running.

Upon substituting $x=0.5$ in expression for time spent in flying jet-packs, we will get:

$2-x\Rightarrow 2-0.5=1.5$

Therefore, Eudora spent 1.5 hours flying using her jet-pack.

7 0

3 years ago

Write a porportion to find how many points a student needs to score on the test to get the given score

horrorfan [7]

The first one is 20. The second one is 64 points

4 0

3 years ago

The department of public safety has an old memo stating that the number of accidents per week at a hazardous intersection varies

ELEN [110]

Answer:

P-value = 0.1515

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 2.2

Sample mean, $\bar{x}$ = 2

Sample size, n = 52

Alpha, α = 0.05

Population standard deviation, σ = 1.4

First, we design the null and the alternate hypothesis

$H_{0}: \mu =2.2\\H_A: \mu < 2.2$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{2 - 2.2}{\frac{1.4}{\sqrt{52}} } = -1.03$

Now, we calculate the p-value from the normal standard table.

P-value = 0.1515

6 0

3 years ago

Given: AD diameter of circle P.<br> If m < 1= 30, then m AB=<br>A) 15<br>B) 30<br>C) 60

statuscvo [17]

The measure of an arc is the size of the corresponding central angle, so angle 1 for AB,

Answer: B

7 0

3 years ago

Read 2 more answers