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garri49 [273]
3 years ago
7

a white tailed deer can sprint up to 30 miles per hour. american bison can run at of up to 3,520 feet per minute. which animal i

s faster and by how many miles per hour. there are 5,280 feet in one mile
Mathematics
1 answer:
Llana [10]3 years ago
7 0
The American Bison is faster.
The White Tailed Deer can run 30 miles per hour (approx. 2,500 feet per minute) while the Bison can run 3520 ft per minute.
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What's the distance between 178 and -395
Svet_ta [14]
178 - (-395)

178 + 395 = 573

the distance between -395 and 178 is 573

hope this helps
4 0
3 years ago
)) What is 2.825 rounded to the nearest whole number?
Shalnov [3]

Answer:

2.83

Step-by-step explanation:

25 round off is equal to 30

so we can write 2.825 = 2.83 in form of 2 digits

83 round off to 80

2.83 is equal to 2.8

4 0
3 years ago
Consider the transpose of Your matrix A, that is, the matrix whose first column is the first row of A, the second column is the
Zarrin [17]

Answer:The system could have no solution or n number of solution where n is the number of unknown in the n linear equations.

Step-by-step explanation:

To determine if solution exist or not, you test the equation for consistency.

A system is said to be consistent if the rank of a matrix (say B ) is equal to the rank of the matrix formed by adding the constant terms(in this case the zeros) as a third column to the matrix B.

Consider the following scenarios:

(1) For example:Given the matrix A=\left[\begin{array}{ccc}1&2\\3&4\end{array}\right], to transpose A, exchange rows with columns i.e take first column as first row and second column as second row as follows:

Let A transpose be B.

∵B=\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]

the system Bx=0 can be represented in matrix form as:

\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right] ................................eq(1)

Now, to determine the rank of B, we work the determinant of the maximum sub-square matrix of B. In this case, B is a 2 x 2 matrix, therefore, the maximum sub-square matrix of B is itself B. Hence,

|B|=(1*4)-(3*2)= 4-6 = -2 i.e, B is a non-singular matrix with rank of order (-2).

Again, adding the constant terms of equation 1(in this case zeros) as a third column to B, we have B_{0}:      

B_{0}=\left[\begin{array}{ccc}1&3&0\\4&2&0\end{array}\right]. The rank of B_{0} can be found by using the second column and third column pair as follows:

|B_{0}|=(3*0)-(0*2)=0 i.e, B_{0} is a singular matrix with rank of order 1.

Note: a matrix is singular if its determinant is = 0 and non-singular if it is \neq0.

Comparing the rank of both B and B_{0}, it is obvious that

Rank of B\neqRank of B_{0} since (-2)<1.

Therefore, we can conclude that equation(1) is <em>inconsistent and thus has no solution.     </em>

(2) If B=\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right] is the transpose of matrix A=\left[\begin{array}{ccc}-4&-8\\5&10\end{array}\right], then

Then the equation Bx=0 is represented as:

\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right]..................................eq(2)

|B|= (-4*10)-(5*(-8))= -40+40 = 0  i.e B has a rank of order 1.

B_{0}=\left[\begin{array}{ccc}-4&5&0\\-8&10&0\end{array}\right],

|B_{0}|=(5*0)-(0*10)=0-0=0   i.e B_{0} has a rank of order 1.

we can therefor conclude that since

rank B=rank B_{0}=1,  equation(2) is <em>consistent</em> and has 2 solutions for the 2 unknown (X_{1} and X_{2}).

<u>Summary:</u>

  • Given an equation Bx=0, transform the set of linear equations into matrix form as shown in equations(1 and 2).
  • Determine the rank of both the coefficients matrix B and B_{0} which is formed by adding a column with the constant elements of the equation to the coefficient matrix.
  • If the rank of both matrix is same, then the equation is consistent and there exists n number of solutions(n is based on the number of unknown) but if they are not equal, then the equation is not consistent and there is no number of solution.
5 0
3 years ago
Please help it is due today
nata0808 [166]

A

Step-by-step explanation:

because i did this and i pass this

3 0
2 years ago
Read 2 more answers
The drug Viagra comes in a quantity of 30 tablets with an AWP of $900. The pharmacy has an agreement with the supplier to purcha
MrRissso [65]

The profit of  5103.5 by making a prescription for 6 tablets.

<h3>What is percentage?</h3>

Percentage, a relative value indicating hundredth parts of any quantity.

The drug Viagra comes in a quantity of 30 tablets with an AWP of $900.

The insurer is willing to pay the AWP less 5% plus a $2.50

900/TAB = X 30 TABS  =$27000

27000 * (0.05)= $1350

27000-1350.00

=$25650 + $2.50

=25652.5 for 30 tablets

For 6 tablets,

= (25652.5 / 30)*6

= 5103.5

Learn more about percentage here:

brainly.com/question/14695543

#SPJ1

5 0
2 years ago
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