Sin D= opp./hyp. = 35/37
cos D= adj./hyp. = 12/37
tan D= opp./ adj. = 35/12
Since, the fundraiser only have three prices for books($2, $5 and $10), the number of $5 book that was sold is 12.
<h3>How to form equation and solve ?</h3>
The fundraiser only have 3 prices for books which are $2, $5 and $10.
There were 6 more $5 books sold than $10 books sold.
Let
x = number of $10 book sold
Therefore,
number of $5 books sold = x + 6
There are 8 more $2 book sold than $10 book sold. Therefore,
number of $2 books sold = x + 8
A total of $250 was raised.
Therefore, the total amount sold forms the following equation:
10x + 5(x + 6) + 2(x + 8) = 250
10x + 5x + 30 + 2x + 16 = 250
17x = 250 - 30 - 16
17x = 204
x = 204 / 17
x = 12
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Answer:
The discount is $4.50. The sale price is $25.50.
Step-by-step explanation:
Discount: 30(.15)=4.50
Sale Price: 30.00-4.50=25.50
Answer:
Step-by-step explanation:
From the given table,
A. The unit rate for each car is,
Car A = 
= 32 miles per gallon
Car B = 
= 34 miles per gallon
Car C = 
= 35 miles per gallon
Car D = 
= 31 miles per gallon
B. From the derived values in A, the car that uses the least amount of gas is Car C.
C. Total distance covered = 496 miles x 4
= 1984 miles
The gallons of gas the Car A would need for the journey can be determined by;
Car A requires 1 gallon for 32 miles
So that for 1984 miles = 
= 62 gallons
Car A would need 62 gallons of gas to make the trip.
D. Amount spent on gas for Car A = $2.12 x 62
= $131.44
E. speed = 
⇒ time = 
Given the for Car A, speed = 68 miles per hour.
time = 
= 29.1765
time = 29 hours
It would take approximately 29 hours for Car A to cover the total distance of 1984 miles.
Using the average rate of change, it is found that the average rate is of:
(1) 2.1 °F per minute
<h3>What is the average rate of change of a function?</h3>
It is given by the <u>change in the output divided by the change in the input</u>.
In this problem:
- At 15 minutes, the temperature was of 90ºF.
- At 45 minutes, the temperature was fo 153ºF.
Hence, in 30 minutes, the temperature increased 63ºF, hence the rate is given by:
r = 63/30 = 2.1 °F per minute.
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