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strojnjashka [21]
3 years ago
15

A monk crossbred plants which can have purple or white flowers and obtained 511 plants with white flowers and 337 plants with pu

rple flowers find the empirical Probability that a plant had each type of flower
Mathematics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

For purple;

P(p) = 337/848 = 0.40

For white;

P(w) = 511/848 = 0.60

Step-by-step explanation:

Given;

Number of plants with purple flowers P = 337

Number of plants with white flowers W = 511

Total T = 337 + 511 = 848

For purple;

the empirical Probability that a plant had purple flowers P(p) is

P(p) = Number of plants with purple flowers/total number of plants

P(p) = P/T

Substituting the values, we have;

P(p) = 337/848 = 0.40

For white;

the empirical Probability that a plant had white flowers P(w) is

P(w) = Number of plants with white flowers/total number of plants

P(w) = W/T

Substituting the values, we have;

P(w) = 511/848 = 0.60

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4 0
3 years ago
A line with a slope of 5 passes through the point (2,10). What is its equation in slope intercept form
My name is Ann [436]

Answer:

The answer is

<h2>y = 5x</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question

Slope / m = 5

Equation of the line passing through point (2 , 10) is

y - 10 = 5(x - 2)

y - 10 = 5x - 10

y = 5x - 10 + 10

<h3>y = 5x</h3>

Hope this helps you

5 0
3 years ago
A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.
Vlada [557]

Answer:

a)  y=12000(2)^{\frac{t}{50}}

b)  Approx. 27,569 bacteria

c)  About 103 minutes

Step-by-step explanation:

a)

This will follow exponential modelling with form of equation shown below:

y=Ab^{\frac{t}{n}}

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}

b)

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>

<u></u>

c)

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103

After about 103 minutes, there will be 50,000 bacteria

4 0
3 years ago
Factor 3xy+21x+9 completely
inn [45]

Answer:

<h2>Hence the second option is the correct answer</h2>

Step-by-step explanation:

In this problem we are required to factor out the given terms as stated in the expression, what is obtainable is that we look for terms(greatest terms) that are common to all the terms in the expression and factor it out.

here is a way to do it

given the following expression

3xy+21x+9

From the expression above we can see that 3 is common to all the terms of the expression so that we have

3(xy+7x+3)

hence the second option is the correct answer

3 0
3 years ago
Decrease 18tonnes by 30%
Tom [10]
18\tonnes -18\ tonnes\ * 30\ \% =18\tonnes -18\ tonnes\ * 0,3 = 18\tonnes -2,4\ tonnes=15,6\ tonnes


5 0
3 years ago
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