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Alexeev081 [22]

3 years ago

5

Through (-9, -5), perpendicular to the y-axis.

1 answer:

kolezko [41]3 years ago

8 0

What are you trying to ask

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aleka has a box for keepsakes that has a volume of 576 cubic inches the length of the box is 12 in and the width is 8 in what is

Vikki [24]

We know that
volume of the box=length*width*height
V=L*W*H----> H=V/[L*W]
V=576 in³
L=12 in
W=8 in
so
H=576/[12*8]----> H=6 in

the answer is
the height of the box is 6 in

5 0

3 years ago

(IMPORTANT PLEASE ANSWER)You are using a hose to fill up your backyard swimming pool on a hot day. Water flows out of the hose a

just olya [345]

Answer:

The independent variable is the m, which is the number of minutes the hose has been running. The dependent variable is the g, which is the gallons per minute.

Step-by-step explanation:

8 0

3 years ago

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Which of the following is a zero of the function F(x)= x³-4x²-7x+10

liubo4ka [24]

The answer is B -4 so ya I think though

7 0

3 years ago

Can someone help me with this please? It's due tomorrow

Strike441 [17]

Answer:

432

Step-by-step explanation:

length X Width X Height = Volume

6 0

3 years ago

Read 2 more answers

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago