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Answer:
The answer to the question is;
The probability that the resulting sample mean of nicotine content will be less than 0.89 is 0.1587 or 15.87 %.
Step-by-step explanation:
The mean of the distribution = 0.9 mg
The standard deviation of the sample = 0.1 mg
The size of the sample = 100
The mean of he sample = 0.89
The z score for sample mean is given by
where
X = Mean of the sample
μ = Mean of the population
σ = Standard deviation of the population
Therefore Z = = -1
From the standard probabilities table we have the probability for a z value of -1.0 = 0.1587
Therefore the probability that the resulting sample mean will be less than 0.89 = 0.1587 That is the probability that the mean is will be less than 0.89 is 15.87 % probability.
Answer:
c
Step-by-step explanation:
Here's how this works:
Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:
In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:
Put everything over the common denominator now:
Since , we will make that substitution:
We could separate that fraction into 2:
×
and
Therefore, the simplification is
sec(x)csc(x)