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Aleks [24]
3 years ago
8

Calculate the answer, express it in scientific notation.

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0
The first one
the first 2 numbers gives a power of 1 then the second gives you 1-4.
1+1-4 is -2 so its the first one
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Improper fraction: 25/3
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A vacuum had been marked down by 20% and solf for $250. What was the original price of the vacuum?
igomit [66]

Answer:

The original price was $312.50

Step-by-step explanation:

If the vacuum was marked down by 20%, that means it was sold for 80% of the full price. It was sold for $250, so 80% of the original price is $250.

Let's set up an equation.

80/100 of x = 250

0.8 • x = 250

Divide both sides by 0.8.

x = 312.50

The original price was $312.50

Hope this helps!

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3 years ago
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Johny can type a 600 word essay in just 8 minutes how long will it take to type a 2,100 word essay?
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It would take Johny 28 mins to type a 2,100 word essay.
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3 years ago
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Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl
katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

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2 years ago
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