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3 years ago

Can someone please help me on this question.

Mathematics

1 answer:

lesya692 [45]3 years ago

4 0

Answer:

Step-by-step explanation:

$3x^{2} + 5x-12=0$

$-12=-5x-3x^{2}$

$(-12=-5x-3x^{2} ) * -1$

$\sqrt{12=5x+3x^{2}$

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Which of the following equations listed below has a radius of 3?

Evgesh-ka [11]

Answer:

Step-by-step explanation:

WE need to convert the given equations into the standard form

(x - a)^2 + (y - b)^2 = r^2 where r = the radius.

x^2 + y^2 + 12x - 20y+ 132 = 0

(x + 6)^2 - 36 + (y - 10)^2 - 100 = -132

(x + 6)^2 + (y - 10)^2 = -132 + 36 + 100 = 4

giving a radius of 2

x^2 + y^2 + 12x - 20y + 55 = 0

will give a right hand side of -55 + 36 + 100 = 81 giving radius 9.

x^2 + y^2 - 12x+ 20y + 127 = 0

- gives right hand side of -127 + 36 + 100 = 9 giving a radius of 3.

8 0

2 years ago

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if 7 men and 5 womean have applied for job and 3 applicants are randomly selected from the probability that 2 are men

barxatty [35]

The probability that 2 men are selected is 49/144

Probability is the likelihood or chance that an event will occur.

If 7 men and 5 women have applied for job, the total number of people that applied will be 12 people

Pr(2 men are selected) = 7/12 * 7/12
Pr(2 men are selected) = 49/144

Hence the probability that 2 men are selected is 49/144

Learn more on probabaility here:brainly.com/question/24756209

3 0

2 years ago

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-/2 points

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

3 years ago

Simplify.

marin [14]

1/2+(3/8−1/8)^2

= 1/2+(2/8)^2

= 1/2+(1/4)^2

= 1/2 + 1/16

= 8/16 + 1/16

= 9/16

Answer

9/16

3 0

3 years ago

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A square has a side length 9 cm.<br><br> What is its area?

Flauer [41]

Answer:30

Step-by-step explanation:

8 0

3 years ago

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