Question

(01.03)

Answer 1

For this case we must solve the following equation:

$\sqrt {x + 5} -3 = 4$

We add 3 to both sides of the equation:

$\sqrt {x + 5} = 4 + 3\\\sqrt {x + 5} = 7$

We raise the square to eliminate the root:

$x + 5 = 7 ^ 2\\x + 5 = 49$

We subtract 5 on both sides of the equation:

$x = 49-5\\x = 44$

Answer:

$x = 44$

Answer 2

Answer:

x=1 if I understood correctly.

Step-by-step explanation:

$\sqrt{x} + 5 + x - 3 = 4$

$\sqrt{x} + 2 + x = 4$

$\sqrt{x} + x = 2$

At this point if you try all the integers, you will find that only 1 is the solution to this equation, because:

$\sqrt{1} + 1 = 2$

$1 + 1 = 2$

$2 = 2$

Hope I helped!