Answer:
The answer is C use a calculator
Step-by-step explanation:
not that hard lol
Answer:
Step-by-step explanation:
a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.
b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).
c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

where 
3x(x+3)^2
3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x
answer
3x^3 + 18x^2 + 27x
Answer:
y = 16 + 3/11
x = -76/11
Step-by-step explanation:
2y - 5x = -2
3y + 2x = 35
__________
(2y - 5x = -2)*3
(3y + 2x = 35)*2
__________
6y - 15x = -6
6y +4x = 70
__________
(6y - 15x = -6) - (6y +4x = 70)
15x - 4x = -6 -70
__________
11x = -76
x = -76/11
__________
3y +2(-76/11) = 35
3y = 35 + 152/11
3y = 13 + 35 + 9/11
3y = 48 + 9/ 11
y = 16 + 3/11