Please Solve for x. (2x+40)° (x-10)
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The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Data;
- Angle = 30 degree
- Opposite = 35
- Adjacent = x
Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.
SOHCAHTOA
Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.
The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Learn more on trigonometric ratio here;