Diego ran 3 kilometers in 20 minutes. andre ran 2,550 meters in 17 minutes. who ran faster

Data on oxide thickness of semiconductors are as follows: 426, 433, 415, 420, 420, 438, 417, 410, 430, 434, 423, 426, 412, 434,

Luda [366]

Answer:

a) 423.458

b) 9.53

c) 1.94

d) 424.5

e) 0.2916

Step-by-step explanation:

We are given the following in the question:

426, 433, 415, 420, 420, 438, 417, 410, 430, 434, 423, 426, 412, 434, 435, 432, 409, 426, 409, 436, 422, 430, 411, 415

a) point estimate of the mean oxide thickness

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10163}{24} = 423.458$

b) point estimate of the standard deviation of oxide thickness

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of squares of differences = 2089.958

$s = \sqrt{\dfrac{2089.958}{23}} = 9.53$

c) standard error of the point estimate

Standard error =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{9.53}{\sqrt{24}} = 1.94$

d) point estimate of the median oxide thickness

Sorted data: 409, 409, 410, 411, 412, 415, 415, 417, 420, 420, 422, 423, 426, 426, 426, 430, 430, 432, 433, 434, 434, 435, 436, 438

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Median =

$\dfrac{12^{th}+13^{th}}{2} = \dfrac{423+426}{2} = 424.5$

e) proportion of wafers in the population that have oxide thickness greater than 430 angstrom

Sample size, n = 24

Number of wafers with oxides greater than 430 angstrom, x = 7

$p = \dfrac{x}{n} = \dfrac{7}{24} = 0.2916$

7 0

4 years ago

A new motorcycle has a value of $8000 every year is value decreased by $500 which function can be used to find why the value of

vredina [299]

F(x) = 500x-8000

500 times the number of years (x), subtracted by the original price (8000)

5 0

3 years ago

john ran 9/10 mile on saturday. he ran 2/5 mile sunday and 3/10 mile on monday. how many more miles did john run saturday than o

zimovet [89]

The number of more miles John ran is 7/5

Saturday = 9/10 mile
Sunday = 2/5 mile
Monday = 3/10 mile

Sunday + Monday = 2/5 + 3/10

= (2+3) / 10

= 5/10

= 1/2

Saturday - (Sunday + Monday)

= 9/10 - 1/2

= (9+5) / 10

= 14/10

= 7/5

Learn more about fraction:

brainly.com/question/11562149

5 0

3 years ago

Help me plz and ill upvote

sveta [45]

6x/12x
6/12 × x/x
1/2 × 1
1/2

the answer is A

4 0

3 years ago

A video rental company offers a plan that includes a membership fee of $5 and charges $1 for every DVD borrowed. They also offer

WINSTONCH [101]

Answer:

for $5 plan if he rents 47 dvd it will pay 47% as one DVS cost 1 $ .

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Diego ran 3 kilometers in 20 minutes. andre ran 2,550 meters in 17 minutes. who ran faster​

Diego ran 3 kilometers in 20 minutes. andre ran 2,550 meters in 17 minutes. who ran faster