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1 year ago

Of the 125 members of the marching band, 42 are in chorus, 78 play

1 answer:

4 0

Using it's concept, it is found that there is a 0.2979 = 29.79% probability that they are in chorus, given that they do not play a sport.

<h3>What is a probability?</h3>

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, 125 - 78 = 47 members of the band do not play a sport, of which 42 - 28 = 14 are in the chorus, hence the probability is given by:

p = 14/47 = 0.2979.

More can be learned about probabilities at brainly.com/question/14398287

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7x(x+1.8)=0 7x(x+1.8)=0 7x(x+1.8)=0 Answer those 3

ahrayia [7]

Answer:

The answer to all of those questions would be x=-1.8

Step-by-step explanation:

7x(x + 1.8) = 0 - Distribute through the Parenthesis -

7x^2 + 12.6x = 0

x(7x + 12.6) = 0

x = 0

7x + 12.6 = 0

7x = -12.6

x = -12.6/7

x = -1.8

so x = 0 or x = -1.8

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3 years ago

Find the GCF of 56 and 46. 2 8 10

Sonbull [250]

Your GCF would be 2.

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3 years ago

Read 2 more answers

I need help solving this problem

Elena L [17]

Use the given values in the compound interest formula to solve for time, n.

A is the final amount of money, $2800
P is the initial or starting amount $1900
i is the interest rate as a decimal 0.025
n is time in years since it annual.

2800 = 1900(1 + 0.025)^n

2800 = 1900(1.025)^n

2800/1900 = (1.025)^n

28/19 = (1.025)^n

take the natural log of both sides to solve for exponent.

ln(28/19) = ln(1.025^n)

power rule of logarithmic moves exponent

ln(28/19) = n*ln(1.025)

ln(28/19) / ln(1.025) = n

put into a calculator

15.7 years = n

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3 years ago

10% of what is 80,000?

Nataly [62]

Answer:

let the no be x ..then,

10% of x =80,000

10x=80,000*100

x=80,00,000/10

x=8,00,000

hence 10%of 8,00,000 is 80,000

6 0

3 years ago

Read 2 more answers

JUST ANSWER PLEASE!!! QUICK

jeka57 [31]

Answer:

Options 1 and 3

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given: the solution for the following system is (2,9)

Px + Qy = R ⇒(1)

Tx + Uy = V ⇒(2)

We will check which system of equation has the same solution.

System A) Px + Qy = R

(P+T)x + (Q+U)y = R+V ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

System B) Px + Qy = R

(P+2T)x + (Q+2U)y = R-2V ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

(P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

System C) (T-P)x + (U-Q)y = V-R ⇒(5)

Tx + Uy = V

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

System D) (T-P)x + (Q+U)y = V-R ⇒(6)

Tx + Uy = V

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) OR (T-P) and (Q-U)

So, system D has not the same solution of (2,9)

System E) (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

Tx + Uy = V

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

Options 1 and 3

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2 years ago