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algol13
3 years ago
8

Brenton’s weekly pay, P(h) , in dollars, is a function of the number of hours he works, h. He gets paid $20 per hour for the fir

st 40 hours he works in a week. For any hours above that, he is paid overtime at $30 per hour. He is not permitted to work more than 60 hours in a week.
Which set describes the domain of P(h)?
Mathematics
1 answer:
scZoUnD [109]3 years ago
3 0

If you read the question you can find some missing information. By googling it , i found the complete question here:

https://e-eduanswers.com/mathematics/question4074483

The set that describes the domain P(h) is {h| 0 ≤ h ≤ 60}.

<u>Step-by-step explanation:</u>

The given function is P(h) where h is the hours that Brenton works weekly.

If he works for 40 hours in a week he will get paid $20 per hour and he will get paid $30 per hour after 40 hours.

But not exceeded more than 60 hours per week.

⇒ P(h)= 20×h for 0 ≤ h ≤ 40 and

P(h) =30×(h-40) for 40 < h ≤ 60.

So the complete time he can work weekly is less than or equal to 60 hours.

Since domain is the set of all values in the function, so it can be written as {h| 0 ≤ h ≤ 60}.

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Step-by-step explanation:

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3 years ago
1.<br> Slope = (7,-1) and 12,-2)
Evgen [1.6K]

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Step-by-step explanation:

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(-2 - -1)/(12-7)

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6 0
2 years ago
Question 1) Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
USPshnik [31]

Question 1)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(G(x)) = 3(2x - 3)^2 + 1

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Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

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8 0
3 years ago
An automobile dealer wants to see if there is a relationship between monthly sales and the interest rate. A random sample of 4 m
SVETLANKA909090 [29]

Answer:

a) y=-6.254 x +75.064  

b) r =-0.932

The % of variation is given by the determination coefficient given by r^2 and on this case -0.932^2 =0.8687, so then the % of variation explained by the linear model is 86.87%.

Step-by-step explanation:

Assuming the following dataset:

Monthly Sales (Y)     Interest Rate (X)

       22                               9.2

       20                               7.6

       10                                10.4

       45                                5.3

Part a

And we want a linear model on this way y=mx+b, where m represent the slope and b the intercept. In order to find the slope we have this formula:

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=278.65-\frac{32.5^2}{4}=14.5875  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=696.9-\frac{32.5*97}{4}=-91.225  

And the slope would be:  

m=\frac{-91.225}{14.5875}=-6.254  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{32.5}{4}=8.125  

\bar y= \frac{\sum y_i}{n}=\frac{97}{4}=24.25  

And we can find the intercept using this:  

b=\bar y -m \bar x=24.25-(-6.254*8.125)=75.064  

So the line would be given by:  

y=-6.254 x +75.064  

Part b

For this case we need to calculate the correlation coefficient given by:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

r=\frac{4(696.9)-(32.5)(97)}{\sqrt{[4(278.65) -(32.5)^2][4(3009) -(97)^2]}}=-0.937  

So then the correlation coefficient would be r =-0.932

The % of variation is given by the determination coefficient given by r^2 and on this case -0.932^2 =0.8687, so then the % of variation explained by the linear model is 86.87%.

6 0
3 years ago
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