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natta225 [31]
3 years ago
7

Trey rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 96 cents for each mile dr

iven. Trey had to pay $246.43
when he returned the truck. For how many miles did he drive the truck?
miles
Mathematics
1 answer:
Lunna [17]3 years ago
6 0

Answer:

238 miles

Step-by-step explanation:

Subtract total cost with truck fee cost which makes it 228.48 then divide by the cost of each mile driven which is 96 cents, so it would be 238 miles

Hope this helps :)

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Bob wants to buy a TV that cost $500 plus 8% tax. He is getting a bonus of $45 and a birthday gift of $85 which he plans to use
Genrish500 [490]

Answer:

He needs to work for 40 whole hours

Step-by-step explanation:

In this question, we are tasked with calculating the amount a Tv will cost Bob in terms of the number of hours he needs to work.

Let’s look at the total cost he has to pay.

a. $500

b. 8% tax = 8/100 * 500 = $40

c. He is paying 2 bills of $35 each making a total of 2 * $35 = $70

The total amount he is to pay is thus; 500 + 40 + 70 = $610

Let’s look at his income ;

a. Bonus $45

b. Birthday gift $85

The total amount of money he has asides his salary to offset the bill is 45 + 85 = $130

The balance to pay from his salary would be $610 - $130 = $480

The number of hours he has to work since he earns $12 per hour would be 480/12 = 40 hours of work

5 0
3 years ago
Read 2 more answers
Lesly has a mug that is 11/12 full of hot chocolate. Lesly drinks 1/6 of the mug. What fraction of the mug still has hot chocola
podryga [215]

Answer:

9/12

Step-by-step explanation:

multiply both by 2 to get 2/12, 11-2=9

8 0
3 years ago
Show me a graph of 6x + 5y < 30
Fittoniya [83]
Here is a graph of <span>6x + 5y < 30</span>

7 0
3 years ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
3 years ago
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Dominik [7]
100/130 = b
20/130 = r
5 0
3 years ago
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