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3 years ago

The length of a room is 20 ft. and its width is 12 ft. What's the perimeter?

Mathematics

2 answers:

sattari [20]3 years ago

7 0

Answer:

Perimeter = 64ft

Step-by-step explanation:

Perimeter is the sum of the sides i.e. length and width

Perimeter = 20+20+12+12 = 64

iren2701 [21]3 years ago

5 0

Answer:

Step-by-step explanation:

20 + 20=40

12 +12 = 24

24+40=64

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Karen is taking a standardized test. The more questions she answers correctly, the greater her final test score will be.

svp [43]

Step-by-step explanation:

independent is questions answered correct

dependent is final test sore.

i think

8 0

3 years ago

Read 2 more answers

Arc length for xy I’ve been stuck on this for a while

Contact [7]

Answer:

12.22

Step-by-step explanation:

There are 360° in a full circle

The circumference of a circle is c = 2πr

----------------------------------

The lenght of the arc will be the portion of the circumferece included in the angle

l = (∅/360) * 2πr

plug in the knowns

l = (70/360) * 2π(10)

l ≈ 12.22

7 0

3 years ago

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ proceed with caution!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .

$39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}$

Simplify this expression.

$-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )$
$-16 \ \pm \ 3.73139$

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

$(-20.5707,-11.4293)$

If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...

We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.

5 0

2 years ago

Geri spent Friday, Saturday and Sunday selling a total of 24 magazines orders for her school.The amounts on those 3 days were co

ryzh [129]

The sale on Friday = x = 6

The sale on Saturday = x+2 = 6 + 2 =8

The sale on Sunday = x+4 = 6+4 =10

Step-by-step explanation:

Let x be the sale of Friday

Then

x+2 will be the sale of Saturday

x+4 will be the sale of Sunday

According to the given statement, that the total sales were 24

$x+(x+2)+(x+4) = 24\\x+x+2+x+4 = 24\\3x+6 = 24\\Subtracting\ 6\ from\ both\ sides\\3x+6-6=24-6\\3x=18\\Dividing\ both\ sides\ by\ 3\\\frac{3x}{3} = \frac{18}{6}\\x=6$

The sale on Friday = x = 6

The sale on Saturday = x+2 = 6 + 2 =8

The sale on Sunday = x+4 = 6+4 =10

Keywords: Linear equations

Learn more about linear equations at:

#LearnwithBrainly

6 0

4 years ago

Is ∆RST ≅ ∆VUT ? Justify your answer below.

BlackZzzverrR [31]

Answer:

Yes.

Step-by-step explanation:

We know <S is congruent to <U. line segment ST is congruent to line segment UT. Also, the line going through T( line segment RV) makes 2 congruent angles. <STU and < UTV are congruent. So triangle RST is congruent to triangle VUT by ASA (angle side angle.)

8 0

3 years ago