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choli [55]
3 years ago
8

Four students are sitting in the first row. In the second row, 4 students sit behind each of those students, and so on. After th

e fourth row is filled, one student leaves from each row. In the fifth row, 2 students sit behind each student in the fourth row. How many students are sitting in the fifth row? Plz help
Mathematics
1 answer:
vovangra [49]3 years ago
4 0
5 students since one student leave each row which means 3 are left . also there are 2 students in the fifth row so you add 3 by 2 which equal 5
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oksian1 [2.3K]

Answer:

ax^{2} +bx+c^{2}=0

Step-by-step explanation:

A quadratic equation is a equation that takes the form: ax^{2} +bx+c^{2} = 0

   Ex. Using our definition of quadratic equations, ax^{2} +bx+c^{2}=0,

          We can set a = 2, b = 1, c = 6:

               2x^{2} +x+6^{2}=0

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          Which can then be solved (if you are trying to solve it) as:

               (2x+9)(x-8)=0

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6 0
3 years ago
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Snezhnost [94]

Answer:

a loss of 72.47

Step-by-step explanation:

I got this answer right on my test

6 0
3 years ago
A box contains 4 bags of flour. The total mass of all 4 bags is 6kg. What is the mass of each bag in grams?
vovangra [49]

Answer:

1500 g

Step-by-step explanation:

To find the mass of each bag, we divide 6 kg by 4.

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6 0
3 years ago
Rewrite in simplest form (-4x+6y-)-(-9x-8y​
Alex Ar [27]

Answer:

5x + 14y

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−4x+6y−(−9x−8y)

Distribute the Negative Sign:

= −4x+6y+−1(−9x−8y)

= −4x+6y+−1(−9x)+−1(−8y)

= −4x+6y+9x+8y

Combine Like Terms:

= −4x+6y+9x+8y

= (−4x+9x)+(6y+8y)

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5 0
3 years ago
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Levart [38]

Hey there! I'm happy to help!

We know that the perimeter is 2L+2W. Le'ts plug in the values 3 and 5 from our ratio and see what our perimeter would be with that.

2(3)+2(5)

6+10

16

How can we get this 16 to 64?

64/16=4

So, we need to multiply this length and width by four to get 64 as our perimeter!

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We can plug this into our perimeter equation

2(12)+2(20)

24+40

64

Therefore, our length is 12 and our width is 20.

Have a wonderful day! :D

5 0
3 years ago
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