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maw [93]
2 years ago
5

A triangle with a base of 16 cm and a height of 9 cm.

Mathematics
1 answer:
bagirrra123 [75]2 years ago
3 0

Answer: 288

Step-by-step explanation:

(16x9)x2

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Radda [10]
A- could be a part and/or a percent

b- 32×25%=8, 32-8=24
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3 years ago
Josh is hiking Glacier National Park. He has now hiked a total of 17 \text{ km}17 km17, start text, space, k, m, end text and is
EastWind [94]

Answer:

The equation to determine the total length in kilometers is  \frac{h}{2} =(17+2)

The total length in kilometers of Josh’s hike is  38 km.

Step-by-step explanation:

Given:

Let the total length in kilometers of Josh’s hike be h.

Now Given that He has now hiked a total of 17 km and is 2 km short of being 1/2 of the way done with his hike.

It means that to reach half of the length of total length Josh needs 2 more km to add in his hiking which is done which is of 17 km.

Framing the above sentence in equation form we get;

\frac{h}{2}=(17+2)

Hence, The equation to determine the total length in kilometers is  \frac{h}{2} =(17+2)

Now Solving the above equation we get;

First we will multiply 2 on both side using Multiplication property we get;

2\times \frac{h}{2}= 2\times(17+2)\\\\h =2\times 19 =38 \ km

Hence,  The total length in kilometers of Josh’s hike is  38 km.

4 0
3 years ago
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Simplify this expression:<br> -(x+2)+4<br><br> i have no idea im not good with math ;(
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ANSWER :

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8 0
3 years ago
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In a fifth grade class 4/5 of the girls have brown hair 3/4 of them have Long hair what fraction have Long brown hair
maxonik [38]
ANSWER: 12/20 or 3/5

4/5 of girls have brown hair
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Answer:

KL = 50

Step-by-step explanation:

∆JML is similar to ∆JNL. it follows that:

[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]

JM = 4 + 20 = 24

JN = 4

JL = 10 + KL

JK = 10

Plug in the values

[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]

[tex] 6 = \frac{10 + KL}{10} [\tex]

Multiply both sides by 10

[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]

[tex] 60 = 10 + KL [\tex]

Subtract 10 from each side

[tex] 60 - 10 = KL [\tex]

[tex] 50 = KL [\tex]

KL = 50

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3 years ago
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