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3 years ago

From the formula MgO how do you know that Mg is the metal?

Chemistry

1 answer:

Damm [24]3 years ago

5 0

In binary ionic compounds the name of the cation (Metal) is first, so that’s how you know.

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Which statement describes the condition in which diamonds form?

eduard

I think it's A but it might be different from your school and mine

4 0

3 years ago

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What is nitrogen state at 20 celcius

SpyIntel [72]

Hi there, I believe that nitrogen turns into a liquid at 20 degrees Celsius. Thererore, the nitrogen state is liquid.

7 0

4 years ago

Choose the letter that best describes the behavior of a substance during a phase change:

velikii [3]

Answer:

/D/ either absorbs or releases energy

Explanation:

During a phase change energy is either absorbed or released.

A phase change is a reversible process which occurs when a substance changes is its state from one form to another.

Phase changes are used to delineate physical changes.

A phase diagram provides a graphic representation of the change.
The diagram can be 2 dimensional or 3 dimensional.

3 0

3 years ago

For the reaction CH3COOH→CH3COO– + H+, which statement is true?

kow [346]

Answer:

For the reaction CH3COOH→CH3COO– + H+

Among the given statements which is the correct statement?

CH3COOH is a Brønsted-Lowry base.

CH3COO– is an Arrhenius base.

CH3COOH is a Brønsted-Lowry acid.

CH3COO– is a Lewis base.

Explanation:

Bronsted acid is the proton donor.

Bronsted base is the proton acceptor.

Arrhenius base is the one that releases OH- ions when dissolved in water.

Lewis base is the one that is an electron-pair donor.

In the given reaction,

CH3COOH→CH3COO– + H+

Acetic acid releases a proton.

So, it is a proton donor.

Hence, It is a Bronsted-Lowry acid.

Third option is the correct answer.

7 0

3 years ago

WHAT IS THE UNBALCNED EQUATION OF Methane burns in oxygen to produce carbon dioxide and water

deff fn [24]

Answer:

$\boxed{CH_{4}+O_2 --> CO_2 + H_2O}$

Explanation:

<h2>Part 1: Naming compound formulas given the names</h2>

<u>Step 1.</u> Methane's formula is $CH_4$ .

<u>Step 2:</u> Oxygen is a diatomic molecule (it exists bonded to itself for stability purposes), so by itself in chemical equations, it is written as $O_2$ .

<u>Step 3:</u> Carbon dioxide is the molecular compound of one atom of carbon and two atoms of oxygen → $CO_2$ .

<u>Step 4:</u> Water is the common name of the compound of two hydrogen atoms and one oxygen atom → $H_2O$ .

<h2>Part 2: Writing the skeleton equation</h2>

<u>Step 1:</u><em> </em>Use the determined formulas for the reactants and plug them into the equation. We are told that methane burns in oxygen -- hinting at a combustion reaction. Therefore, we may infer that these are the reactants that yield the products.

Skeleton equations are written with the reactant(s) on the left -- if there are several, they are separated by an addition symbol (+).

With this information, we may begin our equation: $CH_4 + O_2$ , where $CH_4$ is methane and $O_2$ is the diatomic molecule of oxygen.

<u>Step 2:</u> Use the determined formulas for the products and plug them into the equation. We are told that the methane burns in oxygen to produce carbon dioxide and water. Hence, we can separate these two as we did with the reactants.

Now, our products side of the reaction will look like this: $--> CO_2 + H_2O$ , where $CO_2$ is carbon dioxide and $H_2O$ is water.

<u>Step 3:</u> Write the final equation. All you must do after determining both sides of the equation is simply push them together. Place the reactant side of the equation on the left and the product side of the equation on the right.

This gives us our final equation, $\boxed{CH_4 + O_2 --> CO_2 + H_2O}$ .

Because the problem asks for the unbalanced equation, we do not need to take any further steps of balancing the equation.

5 0

3 years ago

Read 2 more answers