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Zinaida [17]
3 years ago
5

Green plants use light from the sun to drive photosynthesis. photosynthesis is a chemical reaction in which water (H2O) and carb

on dioxide (CO2) chemically react to form the simple sugar glucose (C6H12O6) and oxygen gas (O2). What mass of water is consumed by the reaction of 7.3 g of carbon dioxide?
Chemistry
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

Mass of H₂O is 3.0g

Explanation:

The reaction equation is given as:

        6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Parameters that are known:

Mass of CO₂ used = 7.3g

Unknown: mass of water consumed = ?

Solution

To solve this kind of problem, we simply apply some mole concept relationships.

  • First, we work from the known to the unknown. From the problem, we have 7.3g of CO₂ that was used. We can find the number of moles from this value using the expression below:

        Number of moles of CO₂ =  \frac{mass}{molar mass}

  • From this number of moles of CO₂, we can use the balanced equation to relate the number of moles of CO₂ to that of H₂O:

       6 moles of CO₂ reacted with 6 moles of H₂O(1:1)

  • We can then use the mole relationship with mass to find the unknown.

Workings

>>>>     Number of moles of CO₂ =?

          Molar mass of CO₂ :

              Atomic mass of C = 12g

               Atomic mass of O = 16g

        Molar mass of CO₂ = 12 + (2 x16) = 44gmol⁻¹

     Number of moles of CO₂ = \frac{7.3}{44} = 0.166moles

>>>>>>   if 6 moles of CO₂ reacted with 6 moles of H₂O, then 0.166moles of CO₂ would produce 0.166moles of H₂O

>>>>>> Mass of water consumed = number of mole of H₂O x molar mass

             Mass of H₂0 = 0.166 x ?

Molar mass of H₂O:

                 Atomic mass of H = 1g

                 Atomic mass of O = 16

 Molar mass of H₂O = (2x1) + 16 = 18gmol⁻¹

Mass of H₂O = 0.166 x 18 = 3.0g

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Talja [164]

Answer:

4.5 g/L.

Explanation:

  • To solve this problem, we must mention Henry's law.
  • Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
  • It can be expressed as: P = KS,

P is the partial pressure of the gas above the solution.

K is the Henry's law constant,

S is the solubility of the gas.

  • At two different pressures, we have two different solubilities of the gas.

<em>∴ P₁S₂ = P₂S₁.</em>

P₁ = 525.0 kPa & S₁ = 10.5 g/L.

P₂ = 225.0 kPa & S₂ = ??? g/L.

∴ S₂ = P₂S₁/P₁ = (225.0 kPa)(10.5 g/L) / (525.0 kPa) = 4.5 g/L.

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ale4655 [162]

Answer:

1. The electronic configuration of X is: 1s2 2s2 sp6 3s2

2. The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

3. The formula of the compound form by X and Y is given as: XY

Explanation:

For X to loss two electrons, it means X is a group 2 element. X can be any element in group 2. The electronic configuration of X is:

1s2 2s2 sp6 3s2

To get the electronic configuration of the anion of element Y, let us find the configuration of element Y. This is done as follows:

Y receives two electrons from X to complete its octet. Therefore Y is a group 6 element. The electronic configuration of Y is given below

1s2 2s2 2p4

The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6

The formula of the compound form by X and Y is given below :

X^2+ + Y^2- —> XY

Their valency will cancel out thus forming XY

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When the compound BaCl2 forms , what happens to the Ba and Cl ions
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Ba stays as Ba+2 and Cl stays as Cl-
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You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from
GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

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