Answer:
y=-![\frac{1}{3} x+6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20x%2B6)
Step-by-step explanation:
Slope intercept form is y=mx+b. So, you solve for y by putting x to the other side and dividing by 6. In order it looks something like:
2x+6y=36
2x -2x +6y = 36 =2x
6y=36-2x
y=6-2/6x
y=6-1/3x
Absolute value is a number's distance away from 0. So, all answers are positive. -4/25 is 4/25's away from 0, so your answer is -4/25. To clarify: if you have the absolute value of ANY number, it will always be the positive version of itself.
Let
![P=(P_x,P_y),\quad Q=(Q_x,Q_y)](https://tex.z-dn.net/?f=P%3D%28P_x%2CP_y%29%2C%5Cquad%20Q%3D%28Q_x%2CQ_y%29)
If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:
![M=\left(\dfrac{P_x+Q_x}{2},\ \dfrac{P_y+Q_y}{2}\right)](https://tex.z-dn.net/?f=M%3D%5Cleft%28%5Cdfrac%7BP_x%2BQ_x%7D%7B2%7D%2C%5C%20%5Cdfrac%7BP_y%2BQ_y%7D%7B2%7D%5Cright%29)
We can solve this expression for the coordinates of Q:
![M_x = \dfrac{P_x+Q_x}{2} \implies Q_x = 2M_x-P_x](https://tex.z-dn.net/?f=M_x%20%3D%20%5Cdfrac%7BP_x%2BQ_x%7D%7B2%7D%20%5Cimplies%20Q_x%20%3D%202M_x-P_x)
![M_y = \dfrac{P_y+Q_y}{2} \implies Q_y = 2M_y-P_y](https://tex.z-dn.net/?f=M_y%20%3D%20%5Cdfrac%7BP_y%2BQ_y%7D%7B2%7D%20%5Cimplies%20Q_y%20%3D%202M_y-P_y)
Plug in the values for the coordinates of M and P to get
![Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1](https://tex.z-dn.net/?f=Q_x%20%3D%202M_x-P_x%20%3D%202%5Ccdot%205-11%20%3D%2010-11%3D-1)
![Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6](https://tex.z-dn.net/?f=Q_y%20%3D%202M_y-P_y%20%3D%202%5Ccdot%20%28-2%29%20-%20%28-10%29%20%3D%20-4%2B10%3D6)
Yes. There is sixteen ounces in a pound. At thirty cents an ounce, you can buy a pound for $4.80. That also leaves $.20.
Six now have a good day happy face bye-bye