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katrin [286]
3 years ago
9

8,765,432 A. what number is in the tens place? B. what number us in the hundred thousand place?

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0
First, let's label our decimal places from the ones to the millions.

A number to the left of a decimal is labeled as the 'ones' place.
For example;
9,864,571.23
"9" is in the millions place (the number seven places to the left of a decimal).
"8" is in the hundred-thousands place (the number six places to the left of a decimal).
"6" is in the ten thousands place (the number five places to the left of a decimal).
"4" is in the thousands place (the number four places to the left of a decimal).
"5" is in the hundreds place (the number three places to the left of a decimal).
"7" is in the tens place (the number two places to the left of a decimal).
"1" is in the ones place (the number one place to the right of a decimal).
"2" is in the tenths place (i.e "one tenth").
"3" is in the hundredths place (i.e "one hundredth", or one-out-of-one-hundred).

Our number is
8,765,432.00 (the decimal place is just additional information to assist us in understanding)

Let's look for the number in the tens place.

Remember, the 'tens' place is the number two places to the left of a decimal.

"3" is the number in the tens place.
Your answer for A.) is 3.

Now, let's look for the number in the hundred thousand place.

Remember, the hundred thousands place is six places to the left of a decimal.

"7" is the number in the hundred thousands place.

Your answer for B.) is 7.

Your answers are:

A.) 3
B.) 7

I hope this helps!
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Answer:

g(x + a) - g(x) = 10ax + 5a^2 + 2a

Step-by-step explanation:

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g(x) = 5x^2 + 2x

And we want to determine:

\displaystyle g(x+a) - g(x)

Substitute:

\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right]    \end{aligned}

And simplify:

\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\  \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a)     \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}

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