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Alinara [238K]
4 years ago
10

Scientific procedure followed to obtain results for analysis. This is also a means to test a hypothesis.

Chemistry
1 answer:
eduard4 years ago
8 0
This is a experiment!
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What is the mass in grams of 0.00125 mole of sodium Na=23​
Anit [1.1K]

Answer:

0.03g

Explanation:

Given parameters:

Number of moles of Na = 0.00125mole

Unknown:

Mass in grams of Na = ?

Solution:

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7 0
3 years ago
In an experiment, a student dissolves 56.3g of MgCl2 in 0.12kg of solvent. What is the molality of this solution? Show your work
Kazeer [188]

<u>Answer:</u> The molality of magnesium chloride is 4.93 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}}{M_{solute}\times W_{solvent}\text{ in kg}}

Where,

m_{solute} = Given mass of solute (MgCl_2) = 56.3 g

M_{solute} = Molar mass of solute (MgCl_2) = 95.2 g/mol

W_{solvent} = Mass of solvent = 0.12 kg

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{56.3}{95.2\times 0.12}\\\\\text{Molality of }MgCl_2=4.93m

Hence, the molality of magnesium chloride is 4.93 m

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3 years ago
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