Answer:
Option C. Electrons are shared between two atoms
Explanation:
Covalent bonding is a type of bonding which exist between two non metals.
In this bonding, electrons are shared between the two atoms involved in order to attain a stable octet configuration.
This can be seen when hydrogen atom combine with chlorine atom to form hydrogen chloride as shown below:
H + Cl —> HCl
Hydrogen has 1 electron in it's outmost shell and it requires 1 electron to attain a stable configuration.
Chlorine has 7 electrons in it's outmost shell and requires 1 electron to attain a stable configuration.
During bonding, both hydrogen and chlorine will contribute 1 electron each to form bond, thereby attaining a stable configuration. The bond formed in this case is called covalent bond as both atoms involved shared electron to attain a stable configuration.
Answer:
La distinción entre la química teóricamente teórica y la química avanzada es la química teórica teórica que se basa en un espiritualista, potente que percibe visualmente la autenticidad, mientras que la química espera que la autenticidad sea fundamentalmente mundana. Eso engendra una tremenda distinción, y la química nunca se hubiera alejado excepcionalmente de la remota posibilidad de que se hubiera quedado con el trascendentalismo antediluviano.
Explanation:
True
Carbon monoxide is a primary pollutant which no odor results from incomplete combustion of fuel. The man sources are gasoline and burning of biomass.
Depending on the source of emission, pollutants can be classified into two groups that is primary and secondary pollutants.
A primary pollutant is emitted in the atmosphere directly from a source. It can be either natural sch as volcanic eruptions, sandstorms or man-made that is due to industrial and vehicle emissions. Examples of primary pollutants are nitrogen oxides, carbon monoxide and particulate matter.
Secondary pollutant is due to interactions between primary and secondary pollutants. These can be chemical or physical interactions. Examples are photo-chemical oxidants and secondary particulate matter.
Therefore, carbon monoxide CO is a primary pollutant.
The amount of barium ions that must be present in order for the salt to precipitate is 0.245 M.
A solution's solubility product is the result of raising each ion's concentration to the power of its stoichiometric ratio. It is portrayed as
A combination of 1 barium ion and 2 fluoride ions results in the ionic compound known as barium fluoride.
The following equation describes the equilibrium reaction for barium fluoride ionization:
BaF₂ → Ba²⁺ + 2F⁻
Ksp = [Ba²⁺] · [F⁻]²
2.45*
= [Ba²⁺] * ![[1. 00*10^{-2} ]^{2}](https://tex.z-dn.net/?f=%5B1.%2000%2A10%5E%7B-2%7D%20%5D%5E%7B2%7D)
[Ba²⁺]=0.245 M
As a result, 0.245 M of barium ions must be present in order for the salt to precipitate.
<h3>Solubility </h3>
Solubility in chemistry refers to a chemical's capacity to dissolve in another substance, the solvent, to produce a solution. Inability of the solute to create such a solution is the opposite quality, or insolubility. A substance's degree of solubility in a given solvent is often determined by the amount of the solute present in a saturated solution, which is a solution in which no additional solute can be dissolved. The solubility equilibrium between the two compounds is considered to have been reached at this time. If there is no such restriction for a given solute and solvent, the two are referred to as being "miscible in any amounts."
What concentration of the barium ion, ba2 , must be exceeded to precipitate baf2 from a solution that is 1. 00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2. 45×10−5
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Answer:
0.077 M
Explanation:
Molarity is the representation of the solution.
Molarity:
It is amount of solute in moles per liter of solution and represented by M
Formula used for Molarity
M = moles of solute / Liter of solution . . . . . . . . . . (1)
Data Given :
The concentration of half normal (NaCl) saline = 0.45g / 100 g
So,
Volume of Solution = 100 g = 100 mL
Volume of Solution in L = 100 mL / 1000
Volume of Solution = 0.1 L
molar mass of NaCl = 58.44 g/mol
Now to find number of moles of Nacl
no. of moles of NaCl = mass of NaCl / molar mass
no. of moles of NaCl = 0.45g / 58.44 g/mol
no. of moles of NaCl = 0.0077 g
Put values in the eq (1)
M = moles of solute / Liter of solution . . . . . . . . . . (1)
M = 0.0077 g / 0.1 L
M = 0.077 M
So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M
