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jeka57 [31]
4 years ago
13

Write the electron configurations of cu2+ and ag+. is each electron configuration consistent with the color you observed for eac

h cation? explain.
Chemistry
2 answers:
djverab [1.8K]4 years ago
8 0
(1) Copper:
Copper has the atomic number : 29
Cu2+ means that it lost 2 electrons, therefore, the total number of electrons is 29-2 = 27 electrons.
The electronic configuration is:
1s2 2s2 2p6 3s2 3p6 3d9

(2) Silver:
Silver has atomic number : 47
Ag  + means that it lost one electron, therefore, the total number of electrons  is 47-1 = 46 electrons
The electronic configuration is:
<span>1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10</span>

san4es73 [151]4 years ago
8 0

The electron configuration of copper cation:

₂₉Cu²⁺ 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁹ or [Ar] 3d⁹.

The electron configuration of copper cation:

₄₇Ag⁺ 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ or [Kr] 4d¹⁰.

Copper and silver lose their outer s-orbital electrons before they lose their outer d-orbital electrons.

Each electron configuration is consistent with the color, copper solution is blue, silver solution is colorless.

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The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co
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Answer:

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

Explanation:

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m_{sw} = \rho_{sw}\cdot V_{sw}

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\rho_{sw} - Density of seawater, measured in grams per liters.

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r = \frac{m_{NaCl}}{m_{sw}}

m_{NaCl} = r\cdot m_{sw}

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m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)

m_{NaCl} = 5.408\times 10^{22}\,g

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