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xxMikexx [17]
3 years ago
15

The midpoint of sm is (5,-11). One endpoint is S(3,5). What are the coordinates of endpoint M?

Mathematics
1 answer:
Nitella [24]3 years ago
3 0
The coordinates of the midpoint if the endpoints are (x₁,y₁) and (x₂,y₂):
(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

One endpoint is (3,5), the midpoint is (5,-11). The other endpoint is (x,y).

\frac{3+x}{2}=5 \ \ \ \ \ \ \ \ |\times 2 \\
3+x=10 \ \ \ \ \  |-3 \\
x=7 \\ \\
\frac{5+y}{2}=-11 \ \ \ \ \ |\times 2 \\
5+y=-22 \ \ \  |-5 \\
y=-27

The coordinates of endpoint M are (7,-27).
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A clothing store is tracking how much money adults are spending on clothes each month from their only store. Which description r
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A clothing store is tracking, adults who are spending on clothes each month from their only store then the adults who buy any clothes consider as population of the store.

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So, we cannot consider as population of the store.

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Adults who buy any clothes consider as population of the store.

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6 0
1 year ago
The sum of two numbers is 981. One of the numbers is 703. What is the other number?
victus00 [196]

Answer:

Other number is 278.

Step-by-step explanation:

Given that

a + b = 981

One of the numbers = 703

We assume that it is a ; So

a = 703

Other number = b = ?

Put value of a in a + b

a + b = 981

703 + b = 981

b = 278

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A set of composite numbers less than 12 .express it in listing and set builder methods​
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Given:

A set of composite numbers less than 12.

To find:

The set by listing and set builder methods​.

Solution:

Composite number: A positive integer is called a composite number if it has at least one divisor other than 1 and itself.

Composite numbers less than 12 are 4, 6, 8, 9, 10.

By using the listing method , the given set can be expression as:

Set = {4, 6, 8, 9, 10}

The numbers 4, 6, 8, 9, 10 are greater than 1, less than 12 and non prime numbers.

By using set builder method, the given set can be expression as:

Set = \{x|x\neq P,1

Therefore, the list and set builder notation of the given set are {4, 6, 8, 9, 10} and \{x|x\neq P,1 respectively.

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3 years ago
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