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xxMikexx [17]
3 years ago
15

The midpoint of sm is (5,-11). One endpoint is S(3,5). What are the coordinates of endpoint M?

Mathematics
1 answer:
Nitella [24]3 years ago
3 0
The coordinates of the midpoint if the endpoints are (x₁,y₁) and (x₂,y₂):
(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

One endpoint is (3,5), the midpoint is (5,-11). The other endpoint is (x,y).

\frac{3+x}{2}=5 \ \ \ \ \ \ \ \ |\times 2 \\
3+x=10 \ \ \ \ \  |-3 \\
x=7 \\ \\
\frac{5+y}{2}=-11 \ \ \ \ \ |\times 2 \\
5+y=-22 \ \ \  |-5 \\
y=-27

The coordinates of endpoint M are (7,-27).
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3 years ago
Find the 52nd term for the following sequence. 16,6,-4,-14....
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3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

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Answer:

-38

Step-by-step explanation:

y=2

z=-17

yz-y^2

(2)(-17)-(2)^2

-34-4

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