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Alik [6]
3 years ago
10

An online store can place 6 large boxes or 10 small boxes into a carton for shipping. In one shipment, there were a total of 82

boxes. If there are more large boxes than small boxes, how many cartons were shipped?
(please help T-T)
Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

60 Cartons.

Step-by-step explanation:

To figure this out, you should think about the multiples of 10 boxes you could have.

10 x 6 = 60

Therefore they shipped out 60 cartons.

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Which function has the same y-intercept as the function?<br>​
rosijanka [135]

Answer:

6x -7y = 21

Step-by-step explanation:

The y-intercept of a line is the y value when x = 0. In the equation y = \frac23 x -3 \\, we can solve for its equation when we plug in x = 0.

Solving for y when x = 0:

y = \frac23 x -3 \\ y = \frac23 (0) -3 \\ y = -3.

So the y-intercept of the equation y = \frac23 x -3 \\ is -3.

To find what equation has the same y-intercept, we can do the same process for each equations given by the choices. However, I can see that the equation, 6x -7y = 21, has the y-intercept. If in doubt, you can check for the solution below or solve each equations for yourself.

Solving for y when x = 0:

6x -7y = 21 \\ 6(0) -7y = 21 \\ 0 -7y = 21 \\ -7y = 21 \\ \frac{-7y}{-7} = \frac{21}{-7} \\ y = -3

8 0
3 years ago
If $480 is shared in the ratio 4:3:5, the difference between the largest and the smallest share is
Alex17521 [72]

Answer:

80

Step-by-step explanation:

........

..

the answer is 80

8 0
2 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
2 years ago
Anna has 4 bags of 100 crackers, bags of 10 crackers, and 3 crackers that aren’t in bags. How many crackers does she have
sweet-ann [11.9K]

Answer:1,100??

Step-by-step explanation:

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What is 18% of 900? (please answer quickly!)
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162 is the answer. :)
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