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ludmilkaskok [199]
3 years ago
11

If d divides a and d divides b, prove that d divides gcd(a,b).

Mathematics
1 answer:
Sergio [31]3 years ago
5 0

Answer:

GCD(a,b) is multiple of d. It means d divides GCD(a,b).

Step-by-step explanation:

Let a and b are two unknown numbers.

If d divides a and d divides b, then a and b are multiple of d.

a=d\cdot m=dm

b=d\cdot n=dn

where, m and n are integers.

The greatest common divisor of a and b is

GCD(a,b)=d\cdot m\cdot n

GCD(a,b)=d\cdot mn

GCD(a,b) is multiple of d. It means d divides GCD(a,b).

Hence proved.

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5.
sergij07 [2.7K]

Answer:

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Step-by-step explanation:

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2 years ago
Round 3.656 to the nearest hundredth
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Step-by-step explanation:

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Read 2 more answers
What is the y value of the vertex
Alenkasestr [34]

Answer:

y value = 49

Step-by-step explanation:

You are going to be completing the square

y = - x^2 - 10x + 24           Take a minus outside the brackets for the first 2 terms.

y = - (x^2 + 10x) + 24

Take 1/2 the linear term (1/2 10 and square it. Put that value inside the brackets. 1/2* 10 =5; 5^2 = 25

y = - (x^2 + 10x + 25) + 24

Add 25 outside the brackets.

y = -(x^2 + 10x + 25) + 24 + 25. You should stop here and consider why you are adding 25 outside the brackets. It is because there is a - sign in front of the trinomial and what is inside the brackets is really - 25 when the brackets are removed. Therefore to balance that, you add 25.

Now complete the square.

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The value you seek is 49.

=============

I'll confirm this with a graph.

4 0
3 years ago
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