The answer to your problem A=60
Answer with Step-by-step explanation:
we are given a event of rolling as die several times:
Outcome: [1 2 3 4 5 6]
Number of times outcome occurred: [10 6 4 8 6 6]
We have to find the experimental probability of rolling a 1 or a 5
number of times 1 or 5 came up= 10+6=16
and total number of outcomes= 10+6+4+8+6+6= 40
P( rolling a 1 or a 5)=
number of times 1 or 5 came up/ total number of outcomes
= 16/40
= 2/5
Hence, the experimental probability of rolling a 1 or a 5 is:
2/5
A) What is the mean of : 18, 22, 14, 30, 26
x = (18 +22+ 14+ 30+ 26)/5 = 22
(b) What is the sum of the squares of the differences between each data value and the
mean: (data point - x)² or (data point - 22)²
(18-22)² = 16
(22-22)² = 0
(14-22)² = 64
(30-22)² = 64
(26-22)² = 16
Sum = 16+0+64+64+16 = 160
(c) What is the standard deviation
s = √[(∑(x-22)²/(n-1)], where x is the data point, 20 the mean and n =5
√[(∑(x-22)² = 160 and n = 5 (5 data points) then s = 160(5-1) = 160/4 = 40
d) 32, 35, 33, 34, and 36
Rewrite it from smaller to greater:
32, 34, 34, 35 36.
We notice that the range is from 32 to 36 is only 4 (36-32), Where as the range of the
1st pumpkins is 30-14 = 16
Since the spread of the 1st one is by far larger than the 2nd, we can conclude that the
standard deviation of the 1st is greater than the second
Answer:
Step-by-step explanation:
Remark
A B and D refer to what the cylinder can contain. They all refer to the hollowed out part of the cylinder.
C is the only one that talks about what you need to cover the cylinder with (say) paper or cloth. C is external to the surface of the cylinder.
Answer: C
