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Romashka-Z-Leto [24]
3 years ago
10

Mr. Heath is TRYING to grow his hair out! Currently, his hair is 0.25 inches long. Each month, it grows 0.5 inches. His goal is

to have hair that is 2.5 inches long. Let x be the number of months that Mr. Heath grows hair. Which of the equations represents Mr. Heath's hair growth journey? *
Mathematics
1 answer:
Triss [41]3 years ago
4 0

Answer: 0.25 + 0.5x = 2.5

Step-by-step explanation:

0.25 = the how long his hair is right now

0.5 = how much it grows each month

X= how many months it takes to reach 2.5 inches of hair

2.5= how long he'd like his hair to be

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After working for 25 hours lammer made $375 after working 40 hours lammer made $600 predict how much will he make after 10 hours
Alex
25hr. 40h. 10hr

375$ 600$ x

25 . 40 . x = 1000
375 . 600 = 225000
225000÷1000
x = 225
3 0
4 years ago
No answer text provided.
zheka24 [161]

Answer:

HM > CH

Step-by-step explanation:

You are correct, I didn't see the option HM > CH, which is correct, since the angle 90 degrees is larger than the angle 73, and then the sides opposite to them must follow suit.

Therefore, the correct answer is: HM > CH

5 0
3 years ago
Read 2 more answers
Eliminate the x and y
sp2606 [1]

Step-by-step explanation:

Eliminate the x:

\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by (-3)}\\\\\left\{\begin{array}{ccc}-3(x-2y)=(-3)(6)\\3x+y=4\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-3x+6y=-18\\3x+y=4\end{array}\right}\\.\qquad\qquad7y=-14\\.\qquad\qquad y=-2

Eliminate the y:

\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by 2}\\\\\left\{\begin{array}{ccc}x-2y=6\\2(3x+y)=(2)(4)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-2y=6\\6x+2y=8\end{array}\right}\\\\.\qquad7x=14\\.\qquad x=2

7 0
3 years ago
A flying cannonball’s height is described by formula y=−16 <img src="https://tex.z-dn.net/?f=%20t%5E%7B2%7D%20" id="TexFormula1"
Morgarella [4.7K]
Y = -t ^ 2 + 300t - 16
 We find the first derivative and calculate its roots.
 We make the second derivative, and calculate the sign taken in it by the roots of the first derivative, and if:
 f '' (a) <0 is a relative maximum
 f '' (a)> 0 is a relative minimum

 y '= - 2t + 300 = 0
 -2t + 300 = 0
 t = 300/2 = 150

 y'' = - 2
 y'' (150) = - 2 (is a relative maximum)

 the highest point of the trajectory is reached for t = 150s.
 The height for that time is
 y = - (150) ^ 2 + 300 (150) - 16 = 67484
 
 answer
 67484
 t = 150s.


4 0
3 years ago
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