Answer: (a) IV (b) positive (c) (d) C (e)
<u>Step-by-step explanation:</u>
a) - = , which is located in Quadrant IV <em>per the Unit Circle. </em>
b) sec is . Cos is the x-coordinate. The x-coordinate inQuadrant IV is positive.
c) the reference angle is the angle from to 2π =
d) since the angle is below the x-axis and the reference angle is, then the angle is equal to )
e) sec = ⇒ sec = = = =
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Answer: (a) (b) (0, -1) (c) A (d) -1
a) - = - =
b) is on the Unit Circle at (0, -1)
c) sin = which equals on the Unit Circle.
d) sin is the y-coordinate. sin = -1
Triangle A B C is reflected across BC and then is rotated about point C to form triangle D E C.
1) Since SSS Postulate states that if the three sides of one triangle have the same measure as another triangle then both triangles are congruent.
The consequence of this Postulate is that these triangles have respectively the same angles.
We have given that,
Triangles A B C and D E C are connected at point C.
Triangle A B C is reflected across BC and then is rotated about point C to form triangle DEC.
2) Notice below both triangles SSS, an example, in this case, an isosceles triangle, firstly reflected (grey one ) then rotated by point C.
To learn more same triangle visit:
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Answer:
The factorized expression is
Step-by-step explanation:
The first step to solve this problem is knowing that:
So
Answer:b
Step-by-step explanation: you can correct your self and check your work by doing keep change flip
Answer: 12x^3 + 19x^2 -27x -40
Finding f(x) times g(x) is multiply the two polynomials
(4x+5)(3x^2 + 1x -8) Apply the distributive property twice to solve
4x ( 3x^2 + 1x -8)
12x^3 + 4x^2 - 32x
5(3x^2 + 1x -8)
15x^2 + 5x - 40
12x^3 + 4x^2 - 32x + 15x^2 + 5x -40 now combine like terms
12x^3 + 19x^2 -27x -40