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Hatshy [7]
3 years ago
15

HELP WITH THESE QUESTIONS PART 2.

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

Answer: (a) IV (b) positive (c) \frac{\pi}{4} (d) C (e) \sqrt{2}

<u>Step-by-step explanation:</u>

a) \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4}, which is located in Quadrant IV <em>per the Unit Circle.  </em>

b) sec is \frac{1}{cos}. Cos is the x-coordinate.  The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from \frac{7\pi}{4} to 2π = \frac{\pi}{4}

d) since the angle is below the x-axis and the reference angle is\frac{\pi}{4}, then the angle is equal to -sec(\frac{\pi}{4})

e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

**********************************************************

Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) \frac{11\pi}{2} - \frac{4\pi}{2} = \frac{7\pi}{2} - \frac{11\pi}{2} = \frac{3\pi}{2}

b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

c) sin = \frac{opposite}{hypotenuse} which equals \frac{y}{r} on the Unit Circle.

d) sin is the y-coordinate. sin (\frac{3\pi}{2}) = -1

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