The first one is not proportional and the second one is proportional.
Answer: The equation is y= -2x -4
Step-by-step explanation:
The slope intercept form is like y=mx+b so we know the slope which is m but we just need to find the y intercept.
and we will use the given coordinates to find the y intercept by putting in the x and y coordinates into the formula y=mx + b
-6= -2(1) + b
-6= -2 + b
+2 +2
b= -4
Answer:
(A) - (5)
(B) - (4)
(C) - (1)
(D) - (2)
Step-by-step explanation:
(A) We are given the polynomial (x+4)(x−4)[x−(2−i)][x−(2+i)]
(5) The related polynomial equation has a total of four roots; two roots are complex and two roots are real.
(B) We are given the polynomial (x+i)(x−i)(x−2)³(x−4).
(4) The related polynomial equation has a total of six roots; two roots are complex and one of the remaining real roots has a multiplicity of 3.
(C) We are given the polynomial (x+3)(x−5)(x+2)²
(1) The related polynomial equation has a total of four roots; all four roots are real and one root has a multiplicity of 2.
(D) We are given the polynomial (x+2)²(x+1)²
(2) The related polynomial equation has a total four roots; all four roots are real and two roots have a multiplicity of 2. (Answer)
Answer:
1. z = -1.91429
The z score tells us that the head circumference of the girl with the down syndrome ( 44.5 cm) is 1.91429 standard deviations below the mean or average head circumference
2. 2.7792%
Step-by-step explanation:
1. Relative to the WHO data, what is this girls z-score?
z score formula is:
z = (x-μ)/σ, where
x is the raw score = 44.5 cm
μ is the population mean = 47.18cm
σ is the population standard deviation = 1.40cm
z = 44.5 - 47.18/1.40
z = -1.91429
What does the z score tell us?
The z score tells us that the head circumference of the girl with the down syndrome ( 44.5 cm) is 1.91429 standard deviations below the mean or average head circumference
2. Using the WHO data in a normal model, what percentage of the girls has a head circumference that is smaller than the girl with Down's Syndrome?
z score = -1.91429
Probability value from Z-Table:
P(z =-1.91429) = P(x<44.5) = 0.027792
Converting to percentage = 0.027792 × 100
= 2.7792%
