Question

frac{n^5}{n-6} * \frac{n^2-6}{n^8}" alt="\frac{n^5}{n-6} * \frac{n^2-6}{n^8}" align="absmiddle" class="latex-formula">

Answer 1

Step-by-step explanation:

Dod you mean

$= \frac{ {n}^{5} }{ {n}^{ - 2} } \times \frac{ {n}^{2 - 6} }{ {n}^{8} }$

$= {n}^{5 - ( - 2)} \times {n}^{2 - 6 - 8}$

$= {n}^{7} \times {n}^{ - 12}$

$= {n}^{7 + ( - 12)}$

$= {n}^{ - 5} = \frac{1}{ {n}^{5} }$