Salutations!
<span>There are 318 fiction books in the class library. The number of non fiction book is 47 less than double the number of fictions book. About how many non fiction books are there in the class library?
Let the number of non fiction books me 'NF'.
Let 'F' be fiction
Double means '2', therefore:
2F - 47 = non fiction (NF)
2(318) - 47 = non fiction
As you can see brackets indicate multiplication, therefore you will be multiplying 318 and 2
636 - 47 = non fiction (NF)
Subtract 47 from 636
589 = nonfiction (NF)
There are 589 non fiction books in the library.
Hope I helped (:
Have a great day!</span>
To divide complex numbers in polar form, divide the r parts and subtract the angle parts. Or
<span><span><span><span>r2</span><span>(<span>cos<span>θ2 </span>+ i</span> sin<span>θ2</span>) / </span></span><span><span>r1</span><span>(<span>cos<span>θ1 </span>+ i</span> sin<span>θ1</span>)</span></span></span></span> <span>= <span><span><span>r2/</span><span>r1</span></span></span><span>(cos(<span><span>θ2</span>−<span>θ1) </span></span>+ i sin(<span><span>θ2</span>−θ1)</span><span>)
</span></span></span>
z1/z2
= 3/7 (cos(π/8-π/9) + i sin(π/8 - π/9))
= 3/7 (cos(π/72) + i sin(π/72))
D- (-2,3) :)
hope that helps
First, subtract 5 from both sides, leaving you with 5

- 30x - 5 = 0
If you use the quadratic formula (a=5), (b=-30), (c=-5)
x=-b +/- √b²-4ac / 2a
x= -(30) +/- √(30)² - 4(5) * (-5) / 2(5)
x= 30 +/- √1000 / 10
x = 3 +/- √10