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2 years ago

Which pairs of integers are additive inverses? check all that apply.

Mathematics

1 answer:

dangina [55]2 years ago

6 0

Answer:

A) , C)

Step-by-step explanation:

Additive inverse means that, when the pair of integers are added together, they will equal 0. In this case, your answers are:

a. 4, -4

4 + (-4) = 4 - 4 = 0

c. 5, -5

5 + (-5) = 5 - 5 = 0

A) & C) is your answer. Note that you must have the same number, in which one is positive, and the other negative.

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Zigmanuir [339]

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2 years ago

I need help !! I don’t understand this one

Tasya [4]

Answer:

I think it's the 3rd one

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1 year ago

(36 - 4t) squared.

Flura [38]

Answer: 4(3-t)(3+t)

Step-by-step explanation:

after you find the GCF you will have 4(9-t) squared. since 9 is square you will after to put the square root of 9 (which is 3) into the equation when you factor it further. therefore giving you 4(3-t)(3+t). if you un- factored your equation you would get 4(81-t) because 9x9 is 81 not 3. hope this helps. just learned this too lol

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3 years ago

What is the equation of a line passing through the points (-3,<br> -2) and (2, 0)?

Lostsunrise [7]

Answer:

$y=0.400x+-0.800$

Step-by-step explanation:

Given the following question:

point A = (-3, -2)
point B = (2, 0)

To write the equation of the line that passes through two points we have to write the points in slope intercept form.

Formula for slope intercept:

$y=mx+b$

M is equal to the slope of the two points, so first we need to fine the slope of the two points.

$(-3,-2)=(x1,y1)$
$(2,0)=(x2,y2)$

$m=\frac{y2-y1}{x2-x1}$
$m=\frac{0--2}{2--3} =\frac{2}{5}$
$m=\frac{2}{5} =0.400$

$y=mx+b$
$y=-2$
$m=0.400$
$x=-3$
$-2=0.400(-3)+b$
$0.400\times-3=-1.20$
$-2+1.2=-0.800$
$b=-0.800$

$y=0.400x+-0.800$

Hope this helps.

7 0

2 years ago

A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)

Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}$

5 0

2 years ago