The drawbridge will be at an incline of 10.56 degrees. That is 5.56 degrees more than it's initial incline of 5 degrees.
If you draw a picture of this situation, you will see that you can write a sine ratio with the 11 and 60 (opposite over hypotenuse)
sin(x) = 11/60 Solve the equation for x
x = 10.56
5-4*9= 9
just use the properties
Answer =-3 or -3/1
You can either do rise/run
Or you can find two points on the line and do (y2-y1)/(x2-x1)
Two points on the line are (-1,2) and (-3,-4)
X1=-1 Y1=2
X2=-3 Y2=-4
(y2-y1)/(x2-x1) = (-4-2)/(-3-(-1)) =(-6)/(-3+1)
=-6/-2 = -3
So slope =-3/1 or -3 (same thing)