Answer:
<h2>RrYy and rryy
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Explanation:
1. As given; Round seeds (R) are dominant on wrinkled seeds (r),
Yellow seeds (Y) are dominant on green seeds (g).
In a testcross, between an unknown genotype and a homozygous recessive with wrinkled and green seeds (rryy).
offspring are:
Round and yellow are 53; genotype (R_Y_)
round and green are 49; genotype (R_yy)
wrinkle and yellow are 44; genotype (rrY_)
wrinkled and green are 51 ; genotype (rryy)
Here, the genotype of parents of these offspring would be RrYy and rryy.
Answer: In some organisms, chloroplasts play a vital role in the photosynthesis process. The chloroplast receives sunlight's energy and converts it to sugars. In some organisms, chloroplasts play a vital role in the photosynthesis process.
Explanation:
Answer:
Nonrenewable energy resources, like coal, nuclear, oil, and natural gas, are available in limited supplies. This is usually due to the long time it takes for them to be replenished. Renewable resources are replenished naturally and over relatively short periods of time.
Q1. The answer is 1.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
x = 50% = 50/100 = 0.5
n = ?
(1/2)ⁿ = 0.5
log((1/2)ⁿ) = log(0.5)
n * log(1/2) = log(0.5)
n * log(0.5) = log(0.5)
n = log(0.5)/log(0.5)
n = 1
Q10. The answer is 2.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
Rhyolite #2 has 25% of the parent H remaining:
x = 25% = 25/100 = 0.25
n = ?
(1/2)ⁿ = 0.25
log((1/2)ⁿ) = log(0.25)
n * log(1/2) = log(0.25)
n * log(0.5) = log(0.25)
n = log(0.25)/log(0.5)
n = -0.602 / - 0.301
n = 2
Q3. The answer is 100 million years.
A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):
n = t/H
n = 1
t = ?
H = 100 000 000 years
n = t/H
t = n * H
t = 1 * 100 000 000 years
t = 100 000 000 years<span>
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