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gregori [183]
3 years ago
9

A rectangle's width is one-fifth it's length, and it's perimeter is 180m. Find the dimensions of the rectangle. The length is M

and the width is m
Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
P = 2(L + W)
P = 180
W = 1/5L

180 = 2(L + 1/5L)
180 = 2(6/5L)
180 = 12/5L
180 / (12/5) = L
180 * 5/12 = L
75 = L <=== length is 75m

W = 1/5L
W = 1/5(75)
W = 75/5
W = 15 <=== width is 15m
Darina [25.2K]3 years ago
3 0
12L=720 
L=720/12 
L=60 ANS. FOR THE LENGTH. 
W=60/5=12 ANS. FOR THE WIDTH. 
Evidence: 
144=2*60+2*12 
144=120+24 
144=144
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The following are house prices in Southern California:
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Answer:

A. 875,000

Step-by-step explanation:

Order them by least to greatest and then find the median from there so, 700,000; 750,000; 800,000; 875,000; 1,000,000; 1,160,000; 1,180,000

875,000 is the middle man so there is your answer

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3 years ago
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How to find the area
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Answer:A=bh

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A recetangle is A=bh

A trapezoid is A=1/2 h(b1+b2)

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Sterling silver is an alloy of silver that is 92.5% pure silver. If x grams
nlexa [21]

Answer:

D. 0.925x + 0.88y = 0.91(x + y)  

Step-by-step explanation:

The important point to remember is that the total mass of pure silver is the same on each side of the equation.

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0.925x + 0.88y = 0.91(x + y)

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8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
-8+ 8b = 16 8b+8=16 -8=-8 8b=8
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b = 3 \\ b = 1 \\ 0 \\ b = 1
7 0
3 years ago
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