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mrs_skeptik [129]
3 years ago
6

CAN SOMEONE PLEASE WRITE AN EQUATION TO THIS! I WOULD VERY MUCH APPRECIATE IT!

Mathematics
1 answer:
Tresset [83]3 years ago
7 0
Y=-1/3x-4
is that what you meant? as in y=mx+b form?
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Answer: cookbook $40 and science $15

Step-by-step explanation:

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2 years ago
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Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

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The slope is 3 and the y intercept is -7/4

Step-by-step explanation:

We need to get the equation in the form

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Subtract 12x from each side

12x-12x -4y = -12x +7

-4y = -12x+7

Divide each side by -4

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The slope is 3 and the y intercept is -7/4

8 0
3 years ago
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14. Which number sentence is true if the
valentinak56 [21]

Answer:

D

Step-by-step explanation:

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The correct option here is thus D

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3 years ago
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in this case c^{2} is greater than a^{2} +b^{2} therefore, is it an obtuse triangle.

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