Answer:
Option A is the right answer.
146-4b = 122-1b
Reason: vertical angles
It is A I vsnududuudududu
The averages for each category can be calculated by taking the sum of the values and dividing by the number of values .
Jan Feb March
1)
wages <span>$2,100.00 $2,300.00 $2,000.00
sum of the values = 2100 + 2300 + 2000 = 6400
number of values = 3
average = 6400/3 = $ 2133.33
</span><span>2)
donations $210.00 $230.00 $200.00
</span><span>average = (210 + 230 + 200)/3
= $ 213.33
3)
mortgage $590.50 $590.50 $590.50
</span><span>average = ( 590.50 + 590.50 + 590.50)/3
= $ 590.50
4)
electricity $101.25 $89.75 $80.00
</span><span>average = (101.25 + 89.75 + 80.00)/3
= 271/3
= $ 90.33
5)
water $20.10 $22.30 $24.55
</span><span>average = (20.10 + 22.30 + 24.55)/3
= 66.95/3
= $ 22.32
6)
car loan $172.54 $172.54 $172.54
</span><span>average = (172.54 + 172.54 + 172.54)/3
= $ 172.54
7)
food $200.25 $220.70 $205.50
</span><span>average = (200.25 + 220.70 + 205.50)/3
= $ 208.82
8)
insurance $310.50 $0.00 $0.00
</span><span>average = ( 310.50 + 0.00 + 0.00)/3
= $ 103.50
9)
clothes $0.00 $0.00 $75.00
average = (0.00 + 0.00 + 75.00)/3
= $ 25.00
</span><span>10)
car license fee $0.00 $120.90 $0.00
average = (0.00 + 120.90 + 0.00)/3
= $ 40.30
</span><span>11)
newspaper $0.00 $0.00 $45.00
average = (0.00 + 0.00 + 45.00)/3
= $ 15.00
</span><span>12)</span><span>movies $18.00 $0.00 $36.00
average = (18 + 0.00 + 36.0)/3
= $ 18.00
</span><span>13)
new car $100.00 $100.00 $100.00
average = (100 + 100 + 100)/3
= $ 100.00
</span><span>14)
gasoline $80.00 $70.00 $75.00
average = (80.00 + 70.00 + 75.00)
= $ 75.00
</span><span>15)
car repairs $0.00 $119.00 $0.00
average = (0.00 + 119.0 + 0)/3
= $ 39.67
</span><span>16)
miscellaneous $64.50 $59.25 $72.50
average = (64.50 + 59.25 + 72.50)/3
= 196.25/3
= $ 65.42
</span><span>17)
savings $140.00 $140.00 $140.00
</span>average = ( 140 + 140 + 140)/3
= $ 140.00
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
-0.25 would be -25/100 which can be reduced to -1/4
