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Mariana [72]
3 years ago
12

I NEED HELP ASAP ITS A QUIZ Jim's uncle is four times as old as his nephew Jim. In ten years, Jim's uncle's age will be twenty y

ears more than twice Jim's age. How old is Jim's uncle right now? Type a numerical answer in the space provided. Do not type spaces in your answer.
Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

Jim's uncle is 20 years old right now

Step-by-step explanation:

The number of times Jim's uncle is as old as Jim = 4 times

The age of Jim's uncle in 10 years = 20 + 2 × Jim's age

Let Jim's age = A, and Jim's uncles age = B;

Therefore, from the information in the question, we have;

B = 4 × A........................................(1)

B + 10 = 20 + 2 × A......................(2)

Therefore, by substituting the value of B from equation (1) into equation (2), we have;

B = 4 × A

∴ B + 10 = 20 + 2 × A, gives;

4 × A + 10 = 20 + 2 × A

4 × A - 2 × A  = 20 - 10 = 10

A × (4 - 2) = 10

2 × A = 10

A = 10/2 = 5

A = 5 years

Therefore, Jim's age = A = 5 years

Jim's age = 5 years

B = 4 × A = 4 × 5 years = 20 years

B = 20 years

Jim's uncles age = B = 20 years

Jim's uncles age = 20 years

Therefore;

Jim's uncle is 20 years old right now.

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Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

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\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

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\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

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Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

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Answer:

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