All categories

4 years ago

How many grams of KCl are there for in 10 moles of salt?

1 answer:

4 0

Your first step is determining how many gram of KCl are in every mole of KCl. This can be done by simply looking at K and Cl's atomic mass on the Periodic Table. You add K's atomic mass (39.1g) with Cl's atomic mass (35.45g) to determine that the mass of one mole of KCl is 74.55g. Because you have 10 moles of KCl you multiply 74.55g by 10 to reach your answer of 745.5g.

You might be interested in

What are the 5 ways to identify if a chemical reaction happened?

vlada-n [284]

Answer:

a new substance is formed, if heat is formed, color change, the evolution of gas, and bubbles or fizzing

7 0

3 years ago

What is “monomer” mean?

oksano4ka [1.4K]

it is a molecule* that can be joined with other molecules that are identical to form a polymer*

key words :

a molecule:

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

a polymer:

a substance that has a molecular structure consisting chiefly or entirely of a large number of similar units bonded together

hope this helped, good luck in future studies !

-A

5 0

3 years ago

Someone please help me !!

Bezzdna [24]

Answer:

Explanation:

6 0

3 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

3 years ago

Write an interesting good presentation of acid and base

aleksley [76]

these are sour in taste
corrosive in nature
the turn blue litmus to red when litmus paper is dipped into it
we also eat acids like citric acid in our daily life

bitter in taste
soapy to touch
turn red litmus to Blue
we use bases like milk of magnesia and antacid in our daily life

Hope it helps u

5 0

3 years ago