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Andru [333]
3 years ago
7

V 2 O 5 + H C I V O C 13 + H2 0

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

2VOCl3 + 3H2O. Reaction Information. Shcherbinaite + Hydrogen Chloride = Vanadium(V) Oxytrichloride + Water. Reaction Type

Explanation:

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A salt solution with a volume of 250 mL that contains 0.70 mol NaCl.
uysha [10]
 <span>0.70 mol/0.250 L = 2.8 M</span>
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3 years ago
Which of the following substances is classified as a solution?
Ainat [17]

Answer:

Salt water

Explanation:

Please mark me brainliest and thank me.

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3 years ago
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The complete orbital notation diagram of an atom is shown.
Elan Coil [88]

values of the quantum numbers: -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6

location of the electron: In the 7th energy level away from the nucleus.

Explanation:

From the description of the problem, the magnetic number is given is as -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and the electron is located in the 7th energy level away from the nucleus. Basically, the problem is testing for the understanding of the principal quantum numbers which gives the location of electrons and the magnetic quantum number that shows the spatial orientation of the orbitals.

           The orbital designation of the describe electron is 7d

  1. Magnetic quantum number is limited by the azimuthal quantum number which is the quantum number describing the possible shapes. The azimuthal is given as L= n-1. "n" is the principal quantum number which is 7. Therefore L is 6 and the magnetic quantum numbers are -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
  2. The position of the electron is given by the principal quantum number which represents the main energy level in which the orbital is located or the average distance from the nucleus. Here it is 7.

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brainly.com/question/9288609

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5 0
4 years ago
The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens
son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

<u>Given:</u>

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

<u>To determine:</u>

Total mass of NaCl in kg and in tons

<u>Calculation:</u>

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml

Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g

Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24}  g=4.7*10^{22} g

To convert mass from g to Kg:

1000 g = 1 kg

Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg

To convert mass from g to tons:

1 ton = 9.072*10^6 g

Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons

5 0
3 years ago
Wind turbines are becoming an increasingly popular method of generating a community’s electricity. In wind turbines, wind is use
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The will not affect the wind. When it is windy the wind turns a turbine. Once the wind has gone through the turbine it is just normal wind, none of the wind is lost when this happened
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