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Ksju [112]
3 years ago
12

If a standard vodka martini recipe at La-ti-da Lounge calls for 2.5 oz of premium vodka that sells for $35/liter, .5 oz of dry v

ermouth that sells for $7.99 a liter, and one jumbo gourmet olive for 15 cents, and the martini sells for $15, what is the drink cost percentage?
a. 19.3 percent
b. 14.7 percent
c. 12.5 percent
d. 16.5 percent
Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer: (A) 19.3%

<u>Step-by-step explanation:</u>

\text{Vodka: }2.5\text{ oz }\times\dfrac{\$35}{1\text{ liter }}\times\dfrac{1\text{ liter }}{33.814\text{ oz }}=\$2.59\\\\\text{Vermouth: }0.5\text{ oz }\times\dfrac{\$7.99}{1\text{ liter }}\times\dfrac{1\text{ liter }}{33.814\text{ oz }}=\$0.12\\\\\text{Olive: }\$0.15

Vodka + Vermouth + Olive = Total Cost

$2.59  +   $0.12      + $0.15 = $2.86

\dfrac{\text{cost to make}}{\text{selling price}} = \dfrac{\$2.86}{\$15} = 0.19 = 19\%

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