Answer:
Domain: real numbers
Range: 0 < f(x) < ∞
y-intercept: 1
Asymptote: A horizontal asymptote of y = 0
(
3
x
3
2
y
3
x
2
y
−
1
2
)
−
2
(
3
x
3
2
y
3
x
2
y
-
1
2
)
-
2
Move
x
3
2
x
3
2
to the denominator using the negative exponent rule
b
n
=
1
b
−
n
b
n
=
1
b
-
n
.
⎛
⎝
3
y
3
x
2
y
−
1
2
x
−
3
2
⎞
⎠
−
2
(
3
y
3
x
2
y
-
1
2
x
-
3
2
)
-
2
Multiply
x
2
x
2
by
x
−
3
2
x
-
3
2
by adding the exponents.
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(
3
y
3
x
1
2
y
−
1
2
)
−
2
(
3
y
3
x
1
2
y
-
1
2
)
-
2
Move
y
−
1
2
y
-
1
2
to the numerator using the negative exponent rule
1
b
−
n
=
b
n
1
b
-
n
=
b
n
.
(
3
y
3
y
1
2
x
1
2
)
−
2
(
3
y
3
y
1
2
x
1
2
)
-
2
Multiply
y
3
y
3
by
y
1
2
y
1
2
by adding the exponents.
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⎛
⎝
3
y
7
2
x
1
2
⎞
⎠
−
2
(
3
y
7
2
x
1
2
)
-
2
Change the sign of the exponent by rewriting the base as its reciprocal.
⎛
⎝
x
1
2
3
y
7
2
⎞
⎠
2
(
x
1
2
3
y
7
2
)
2
Use the power rule
(
a
b
)
n
=
a
n
b
n
(
a
b
)
n
=
a
n
b
n
to distribute the exponent.
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(
x
1
2
)
2
3
2
(
y
7
2
)
2
(
x
1
2
)
2
3
2
(
y
7
2
)
2
Simplify the numerator.
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x
3
2
(
y
7
2
)
2
x
3
2
(
y
7
2
)
2
Simplify the denominator.
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x
9
y
7
Answer:
m ≥ 3
m is greather or equal to 3
Step-by-step explanation:
m + 4 ≥ 7
m ≥ 7 - 4
m ≥ 3
Answer: he was 84 years old when he died and the fractional part of a century that he live is 21/25
Step-by-step explanation:
General Douglas MacArthur, one of the leading generals in World War II was born in 1880. He died in 1964. The number of years that he lived would be the year he died - the yea he was born. Therefore,
His age when he died
= 1964 - 1880 = 84 years.
The number of years in a century is 100. Therefore, the fractional part of a century that he lived would be
84/100 = 21/25
