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pshichka [43]
2 years ago
15

A kite flying in the air has a 10-ft line attached to it. It’s line is pulled taut and casts a 7-ft shadow. Find the height of t

he kite. if necessary round your answer to the nearest tenth
Mathematics
1 answer:
jasenka [17]2 years ago
6 0

Answer:

If the kite has an 11 ft line attached to it and it casts an 8 feet shadow, we will have a rectangle triangle (see picture below).

To find the height x of the kite, we can apply the Pythagorean theorem.

x² = 11² - 8²

x² = 121 - 64

x² = 57

x =√57 Step-by-step explanation:

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prohojiy [21]
<h3>Answer:</h3>

A. 28

<h3>Step-by-step explanation:</h3>

We assume m is the measure of the marked unknown angles: ∠BZY ≅ ∠BZA

(5x +3)° = (2x +18)°

Divide by ° and subtract 2x+3:

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3 years ago
Solve the given system of equations.
Goryan [66]
The given equations are:
1) 2y = -x + 9 
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2) 3x - 6y = -15
⇒3x = 6y - 15
x = 2y - 5

Equating the values of x, we get:

9 - 2y = 2y - 5
9 + 5 = 4y
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Using this value of y in equation 1 we get:

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So, the solution set is (2, 3.5)

8 0
3 years ago
What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3
Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

                                         = 11 × 8

                                         = 88 square units

Area of trapezoid OGEF = \frac{1}{2}(b_1+b_2)\times h

                                         = \frac{1}{2}(\text{GE+OF)}\times (\text{OG})

                                         = \frac{1}{2}(3+6)\times 4

                                         = 18 units²

Area of trapezoid GCDE = \frac{1}{2}(\text{GC+DE)}\times (\text{GE})

                                         = \frac{1}{2}(7+2)\times 3

                                         = 13.5 units²

Area of triangle AFH = \frac{1}{2}(\text{Base})\times (\text{Height})

                                  = \frac{1}{2}(5)(2)

                                  = 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

                                           = 88 - (18 + 13.5 + 5)

                                           = 88 - 36.5

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Therefore, area of the given polygon is 51.5 units²

3 0
3 years ago
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Answer: B) Dilate by scale factor of 2

====================================================

Explanation:

Your teacher isn't saying this directly, but I'm assuming s/he wants you to find a similar figure that isn't congruent to the original. Informally, your teacher seems to want you to find a figure that is the same shape but not the same size as the original.

If so, then any dilation will shrink or enlarge the image depending on the scale factor. So the new image will not be the same as the old one. In this case, a dilation with scale factor 2 means the new figure is twice as large (each side is twice as long). But the old image is similar to the new image. The angles keep their values and therefore we get the same shape. This is why choice B is the answer. Again this is assuming what I mentioned in the first paragraph.

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