Answer:
Step-by-step explanation:
Part A
x-intercepts of the graph → x = 0, 6
Maximum value of the graph → f(x) = 120
Part B
Increasing in the interval → 0 ≤ x ≤ 3
Decreasing in the interval → 3 < x ≤ 6
As the price of goods increase in the interval [0, 3], profit increases.
But in the price interval of (3, 6] profit of the company decreases.
Part C
Average rate of change of a function 'f' in the interval of x = a and x = b is given by,
Average rate of change = 
Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,
Average rate of change = 
= 
= 30
1 minute 8.25 seconds per mile
Answer:
His money earned $36 after 3 months
Step-by-step explanation:
* Lets revise the rules of simple interest
- Simple Interest Equation (Principal + Interest)
A = P(1 + rt)
- Where:
• A = Total amount (principal + interest) future amount
• P = Principal Amount
• I = Interest Amount
• r = Rate of Interest per year in decimal; r = R/100
• t = Time Period involved
* To calculate the interest I use the formula
I = P × r × t
* Lets solve the problem
- The rate is annual
- The interest calculated after 3 months
∴ I = P × R/100 × t/12
∵ P = $3600.00
∵ R = 4%
∵ t = 3 month
∴ I = 3600.00 × 4/100 × 3/12 = $36
* His money earned $36 after 3 months