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9966 [12]
4 years ago
6

Describe how you would draw the electron dot structure for bromine and then draw the structure.

Chemistry
2 answers:
RideAnS [48]4 years ago
7 0
The electron dot structure shows all of the electrons an atom possesses in its valence, or outer-most, shell. 
Bromine is in the seventh group of the periodic table, the halogens, so it has seven valence electrons. In order to represent, we simply write "Br", the chemical symbol of bromine and draw a circle around it with seven dots, each dot representing one valence electron.
forsale [732]4 years ago
6 0

Answer: Electron dot structures are the structures which represent the valence electrons of the element around the chemical symbol of the element.

Bromine is an element which belong to group 17 and is a halogen. Atomic number of bromine is 35 that means it contains 35 electrons, Thus the electronic configuration is represented as:

[Ar]3d^{10}4s^24p^5

Thus the valence electrons are 7. Thus 7 electrons are represented around chemical symbol of Bromine i.e. Br.



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How many grams are in 4.65 mol of AI(NO2)3
nirvana33 [79]
To find out how many grams are in 4.65 moles of Al(NO₂)₃
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Answer:

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7. 33.4 g (3 s.f.)

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Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

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= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

= 8.16 \times 10^{ - 6} \:  kg

\boxed{density =  \frac{mass}{volume} }

Density of iron bar

=  \frac{0.0642}{8.16 \times 10^{ - 6} }

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7.

\boxed{mass = density \:  \times volume}

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= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

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= 12 cm³

= 12  \times  10^{ - 6}  \: m^{3}  \\  = 1.2 \times 10^{ - 5}  \: m ^{3}

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= 151 g

= 151 ÷ 1000 kg

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3 years ago
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klemol [59]

Answer:

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