Answer:
12 Ethene gas, CH is completely burned in excess oxygen to form carbon dioxide and water
The equation for this exothermic reaction is shown.
CH 30, - 200, 2H,0
The table shows the bond energies involved in the reaction
bond
bond energy
(kJ/moly
614
413
C-C
CHH
0 0
СО
495
799
O-H
467
What is the total energy change in this reaction?
A-954 kJ/mol
B-1010 kJ/mol
C-1313 kJ/mol
D-1359 kJ/mol
Explanation:
thats all you said
Answer: The original volume in liters was 0.0707L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.85 atm
= final pressure of gas = 456 mm Hg = 0.60 atm (760mmHg=1atm)
= initial volume of gas = ?
= final volume of gas = 94.0 ml
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
(1L=1000ml)
Thus the original volume in liters was 0.0707L
Answer:
J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged "soup."
The limiting reagent is <u>H₂SO₄</u>
<u><em>calculation</em></u>
<u><em> </em></u>Step 1 :write the equation for reaction
2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O
Step 2: use the mole ratio to determine the moles of product produced from each reactant
that is from equation above,
NaOH : Na₂SO₄ is 2 :1 therefore the moles of Na₂So₄
= 10.0 moles x 1/2 = 5.0 moles
H₂SO₄ :Na₂SO₄ is 1:1 therefore the moles of Na₂SO₄ is also = 3.50 moles
H₂SO₄ is the limiting reagent since it produces less amount of Na₂SO₄
